Answer:
The atoms of each element have a characteristic number of electrons arranged in electron shells. The number of valence electrons determines what types of bonds or ions the atoms may form, so the chemical reactivity of an atom arises from its electron distribution. The properties of compounds emerge from the arrangement of their constituent atoms and of the bonds between them.
Thus, a wide variety of molecules with very different chemical properties can be made from the same basic atoms. Each molecule has a distinctive size, shape, and charge distribution, which determine its highly specific ability to interact with other molecules.
Compounds in chemical wastes may contaminate the environment if their atoms are combined in new arrangements that harm living organisms.
Explanation:
Answer:
C. "Because you have had one child with Tay-Sachs, you must each carry the allele. Any child you have has a 25% chance of having the disease
Explanation:
Tay-Sachs disease is an autosomal recessive disorder that means a child will acquire the phenotype or we can say disease only when both the alleles which cause disease are present in the child.
Here, in this condition neither parent has Tay-Sachs but they gave birth to a child who is suffering from the disease then it simply means that both the parents are carrier of this disease i.e. they both are heterozygous.
The cross and probability of healthy and diseased child is shown as under:
Mother Father
Parents Tt Tt
/ | | \
Off-springs TT Tt Tt tt
<u>Out of these 4 probable off-springs only 3 with genotype TT, Tt & Tt will be healthy while the 1 with genotype tt will be diseased.</u><u> </u><u>So, the probability of diseased child is 1/4 which is 25%. </u>
Also, the birth of children is an independent event so if one child has already been born with this disease then it doesn't mean that the next 3 children will be healthy for sure i.e. birth of first child cannot influence the next child. In short we can also say that in the next birth, there is still 25% chance of the child being born with this disease because previous birth has nothing to do with next birth.
The probable genotype of the IV-3 with the perspective of autosomal inheritance will be A because he does not have condition A. Therefore both parents must be in condition A.
The probable genotype of IV-3 with the perspective of set=linked inheritance will be BbY this is because he has B condition. Therefore the mothers' genotype must be XBXb and the father's genotype must be XBY.
The probability of IV-4 having condition A is 1/36
Answer:
Explanation:
No because it will expire
They are both types of STD's
