Answer:
The best approximation is 
Step-by-step explanation:
we know that
The area of the circle is equal to

In this problem we have


substitute

The answer is .426 or .43 depending on what you round to. The equation for density is
D=m/v so D= 239.2/92 will give you the answer to your problem.
Answer:
Length of the thread = 30 metres
Step-by-step explanation:
Length of the thread in one round of a reel = Circumference of the reel
C = 
Since radius of the reel = 
= 
= 2.5 cm
Circumference of the reel = 2(π)(2.5)
= 5π
= 5×3
= 15 cm
Length of the thread wound in one round around the reel = 15 cm
Since, thread is wound 200 times round a reel, length of the thread
= 200 × 15
= 3000 cm
≈ 30 metres
Therefore, Option (B) will be the answer.
It’s a semicircle, so it would be 1/2 pi r^2.
If John charge $12 then he has 14 students, and he gets $ 14*12,
If he increases on $2(12+2) , he loses 1 student (14-1), gets (12+2)*(14-1)
if he increases on he loses 2 students (14-2) gets (12+2*2)(14-2)
2+2 (12+2*2)
if he increases 2*3 he loses 3 students, (14-3) gets (12+2*3)(14-3)
2x*3 (12+2*3)
and so on......
if he increases 2*x, he loses x students, (14-x)left, gets (12+2x)(14-x)
(12+2x)
So , his revenue in general =
(12+2x)(14-x)=12*14-12x+28x-2x²=-2x²+16x+168
<em> I think it should look like this
</em>c(x)= -2x²+16x+168