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IceJOKER [234]
3 years ago
14

What is the value of this expression when a 3 and 27

Mathematics
1 answer:
Leya [2.2K]3 years ago
3 0

Step-by-step explanation:

\bigg(  \frac{3 {a}^{ - 2}  {b}^{6} }{2 {a}^{ - 1}  {b}^{5} } \bigg)^{2}  \\  \\  =  \bigg(  \frac{3  {b}^{6 - 5} }{2 {a}^{ 2- 1} } \bigg)^{2}   \\  \\  =  \bigg(  \frac{3  {b}^{1} }{2 {a}^{  1} } \bigg)^{2}   \\  \\  =  \bigg(  \frac{3  {b}}{2 {a}} \bigg)^{2}   \\  \\   =  \bigg(  \frac{3   \times ( - 2)}{2  \times 3} \bigg)^{2}  \\  \\  = \bigg(  \frac{ - 6}{6} \bigg)^{2}  \\  \\  = ( - 1)^{2}  \\  \\ \huge\red {\boxed {\therefore \:    \bigg(  \frac{3 {a}^{ - 2}  {b}^{6} }{2 {a}^{ - 1}  {b}^{5} } \bigg)^{2}  = 1}} \\

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What is the best approximation for the area of this circle? Use 3.14 to approximate pi. 25.1 in² 50.2 in² 201.0 in² 803.8 in² Ci
Greeley [361]

Answer:

The best approximation is 201.0\ in^{2}

Step-by-step explanation:

we know that

The area of the circle is equal to

A=\pi r^{2}

In this problem we have

r=8\ in

\pi =3.14

substitute

A=(3.14)(8^{2})=201.0\ in^{2}

5 0
3 years ago
Read 2 more answers
obsidan is another type of igneous rock what is the density of a obsidian that has a mass of 239.2 and a volume of 92
horsena [70]
The answer is .426 or .43 depending on what you round to. The equation for density is

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6 0
4 years ago
A thread is wound 200 times round a reel of diameter 5 cm. Use the value 3 for it to find the approximate length of the thread i
Radda [10]

Answer:

Length of the thread = 30 metres

Step-by-step explanation:

Length of the thread in one round of a reel = Circumference of the reel

                                                                    C = 2\pi r

Since radius of the reel = \frac{\text{Diameter}}{2}

                                       = \frac{5}{2}

                                       = 2.5 cm

Circumference of the reel = 2(π)(2.5)

                                           = 5π

                                           = 5×3

                                           = 15 cm

Length of the thread wound in one round around the reel = 15 cm

Since, thread is wound 200 times round a reel, length of the thread

= 200 × 15                                                      

= 3000 cm

≈ 30 metres

Therefore, Option (B) will be the answer.

0 0
3 years ago
How do you find the area of the circle?
Lena [83]
It’s a semicircle, so it would be 1/2 pi r^2.
3 0
4 years ago
Read 2 more answers
Please help me with this<br> THANKS TO ALL HELPFUL USERS
Tpy6a [65]
If John charge $12                   then he has 14 students,         and he gets $ 14*12,
If he increases on $2(12+2)  , he loses 1 student (14-1),           gets (12+2)*(14-1)
if he increases on                    he loses 2 students (14-2)         gets (12+2*2)(14-2)
2+2 (12+2*2) 
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2x*3  (12+2*3)
and so on......
if he increases 2*x,        he loses x students, (14-x)left,   gets (12+2x)(14-x)
(12+2x)

So , his revenue in general =
(12+2x)(14-x)=12*14-12x+28x-2x²=-2x²+16x+168

<em> I think it should look like this
</em>c(x)= -2x²+16x+168

5 0
3 years ago
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