By using distance formula (which is attached below), you can solve this problem:
√(x2-x1)^2+(y2-y1)^2
(5, -1) and (5, 3)
√(5-5)^2+(3-(-1))^2
√0^2+4^2
√0+16
√16
4
The distance between the two points is 4.
The equation of the line that contains (−6, 19) and (−15, 28), in standard form, is: x + y = 13
<em><u>Recall:</u></em>
- Equation of a line can be written in standard from as Ax + By = C, where Ax and By are all terms of variable x and y, and C is a constant.
- The equation of a line in point-slope,
, can be rewritten in the standard form.
- Slope (m) =

Given: (−6, 19) and (−15, 28)
<em>Find the </em><em>slope </em><em>(m):</em>
<em />
Write the equation in point-slope form by substituting m = -1 and
into
.


Therefore, the equation of the line that contains (−6, 19) and (−15, 28), in standard form, is: x + y = 13
Learn more about equation of a line in standard form on:
brainly.com/question/19169731
Answer:
156 ≤ 5 (Which is wrong)
Step-by-step explanation:
You start with:
16(6)+20(3) ≤ 5
96+60 ≤5
156 ≤5
Which is wrong.