Answer:
The options are
A. Telophase
B. Anaphase
C. Interphase
D. Metaphase
E. S phase
The CORRECT ANSWER IS A.
A. Telophase
Explanation:
In prometaphase, the nuclear envelope fragments and the kinetochores both attaches itself to the microtubules.
At telophase, fragments of the nuclear envelope start to bind together with fragments of the endomembrane system.
These are all phases of cells multiplying without this we would all be one cell organisms
<u>Bone tissue</u>
You are observing a tissue under the microscope and notice dark concentric circles of matrix and osteocytes in lacunae. You identify this tissue as <u>bone tissue.</u>
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<h3>What does bone tissue look like?</h3>
- Osteons or haversian systems are tightly packed together to form compact bone.
- The osteon is made up of concentric rings (lamellae) of matrix surrounding a central canal known as the osteonic (haversian) canal.
- The bone cells (osteocytes), which are situated between the rings of matrix, are found in regions known as lacunae.
<h3>Which 4 tissues are present in bones?</h3>
- Osteoblasts, osteocytes, osteoclasts, and osteogenic cells are the four types of bone cells that make up bone tissues.
<h3>How does bone tissue develop?</h3>
- The recruitment and growth of bone progenitor cells from neighboring tissues is the first step in the development of bone tissue.
- Next come differentiation, matrix production, and mineralization.
To learn more about bone tissue visit:
brainly.com/question/14363351
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Answer:
The correct answer is -
1. Based on height he is 50% and height he is 25%
2. The nutritional needs are normal due to the constant percentage in both height and weight throughout.
Explanation:
By the reference of the chart of growth rate presented by CDC,
These informations can be found-
Weight :
A= 50%
B=50%
C=50-75%
Height :
D=10-25%
E=25%
F=25%
Then the percentage of height by weight ratio
Height by weight%:
G=75-90%
H=75-90%
I=75-90%
Thus, the correct answer is -
1. Based on height he is 50% and height he is 25%
2. The nutritional needs are normal due to the constant percentage in both height and weight throughout.