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FromTheMoon [43]

3 years ago

10

In Triangle XYZ below, x2+y2=z2.

1 answer:

choli [55]3 years ago

8 0

4, 2, 1, 3

we cannot use 2 before having another triangle, so 4 must be before 2

we can use 1, but it will be just a restatement of the given information is not done before 4 and 2

3 is the final goal, which is always the last step

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60 PTS PLS ANSWER WILL AWARD BRAINLIEST ASAP

pishuonlain [190]

Answer:

9. a) 180 - (55+90) = a

b) a=35 degrees

10. a) 2w + 3w + 40 = 180

b) w=28

c) 2w=56 3w=84

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

(sin x)(tan x cos x - cot x cos x) = 1 - 2 cos2x

Aliun [14]

As

$\tan x=\dfrac{\sin x}{\cos x}$
$\cot x=\dfrac{\cos x}{\sin x}$

we have

$\sin x(\tan x\cos x-\cot x\cos x)=\sin x\left(\sin x-\dfrac{\cos^2x}{\sin x}\right)=\sin^2x-\cos^2x$

Recalling that $\cos2x=\cos^2x-\sin^2x$ , we end up with

$-\cos2x=1-2\cos2x$
$1=\cos2x$
$\implies2x=2n\pi$

(where $n$ is any integer)

$\implies x=n\pi$

5 0

3 years ago

Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball

Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and $51\frac{1}{3}$ yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from $51\frac{1}{3}$ yards.

$\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}$

Let us have a common denominator.

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}$

$\text{1 yard}=3\text{ feet}$

$\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}$

$\frac{28}{3}\text{ yards}=28\text{ feet}$

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0

3 years ago

The perimeter of the rectangle is 20\text{ cm}20 cm20, start text, space, c, m, end text. One side is 6\,\text{cm}6cm6, start te

Tamiku [17]

Answer: The lenght of the missing side is 4 cm

Step-by-step explanation:

The correct question is:

<em>The perimeter of the rectangle is 20cm . One side is 6cm. What is the length of the missing side?</em>

So, to answer it we have to apply the next formula:

Perimeter of a rectangle = 2 width + 2 length

Replacing with the values given: (assuming that the side given is the length of the rectangle)

20 = 2(6) + 2x

Solving for x:

20 =12 +2x

20-12 =2x

8 =2x

8/2 =x

4=x

The length of the missing side is 4 cm

Feel free to ask for more if needed or if you did not understand something.

3 0

3 years ago

Read 2 more answers

The length of a rectangular garden is 7ft more than the width. The perimeter is 50 ft. Find the width.

Vilka [71]

<h2>Answer:</h2>

<em>W=9</em>

<h2>Step-by-step explanation:</h2>

<em>Hope this helps, here is the answer please mark Brainliest.</em>

8 0

2 years ago