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denis-greek [22]
3 years ago
11

Can someone walk me through this?

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
3 0
So you can set up proportion.

\dfrac{7.5\ \text m}{76^\circ} = \dfrac C{360^\circ}

Here, you need to solve for C.

You can do that by multiple both sides by 360 and then you should get 360^\circ\cdot\dfrac{7.5\ \text m}{76^\circ} = C \approx \boxed{35.526\ \text m}

Hope this helps.
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a person is standing on top of a smaller building looking across the street at a taller building, which is 260 feet away horizon
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The height of the smaller building is <u>94.63 feet</u>, computed using the trigonometric ratios.

In the question, we take AB to be the taller building, where A is its top and B is its base, CD to be the shorter building, where C is its top and D is its base, and CE to be the perpendicular from C to AB.

Given that the horizontal distance between the two buildings is 260 feet, we can say that BC = CE = 260 feet.

The angle of elevation from the top of the shorter building to the top of the taller building is 30°, that is, ∠ECA = 30°.

The angle of depression from the top of the shorter building to the base of the taller building is 20°, that is, ∠ECB = 20°.

When ∠ECB = 20°, then ∠CBD = 20°, as they are alternate angles.

We are asked to find the height of the shorter building, that is, we are asked to find CD.

In ΔCBD,

tan ∠CBD = CD/BD {perpendicular/base},

or, tan 20° = CD/260,

or, CD = 260*tan 20° = 260*0.36397023426 {∵ tan 20° = 0.36397023426},

or, CD = 94.6322609092.

Therefore, the height of the smaller building is <u>94.63 feet</u>, computed using the trigonometric ratios.

Learn more about heights and distances at

brainly.com/question/2004882

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