All categories

3 years ago

If someone drank 3 fourthes of a 16 ounce bottle . how many ounces are left

2 answers:

4 0

How many fourths are there in 16 wholes?

$\bf 16\implies \cfrac{16}{1}\implies \cfrac{16\cdot 4}{1\cdot 4}\implies \stackrel{\textit{fourths in 16 wholes}}{\cfrac{64}{4}}
\\\\\\
\textit{now someone takes away }\frac{3}{4}\textit{ from that}\qquad \cfrac{64}{4}-\cfrac{3}{4}
\\\\\\
\cfrac{64-3}{4}\implies \stackrel{leftover}{\cfrac{61}{4}}$

7nadin3 [17]3 years ago

3 0

Look at the demoninator, 1/4 of 16 is 4 ,you have 3 fourths so multiply 4 by 3 and you get 12 16-12 and the answer is 4

You might be interested in

How to find the perimeter and area

Ad libitum [116K]

For Perimeter you add all the sides of the figure and the total is your perimeter. For Area you multiply the length times the width.

3 0

3 years ago

Solve for V.<br> 3y=39<br> Simplify your answer as much as possible.

Crank

Answer:

3y=39 :3

y=13

Step-by-step explanation:

prove me wrong

3 0

3 years ago

Consider the following two expressions, the only difference being the presence or absence of parentheses. expression 1:expressio

PilotLPTM [1.2K]

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

7 0

4 years ago

X -5 -4 -3 -2 -1 0 1 2 3 f(x) -11 -3 5 13 21 29 37 45 53 (a) Determine the difference of outputs of any two inputs that are 1 un

alex41 [277]

A) I use x=-5; f(x)=-11 and x=-4; f(x)=-3. We get the range = -3-(-11)=8b)I use x=-5; f(x)=-11 and x=-3; f(x)=5. We get the range = 5-(-11)=16c)I use x=-5; f(x)=-11 and x=-2; f(x)=13. We get the range = 13-(-11)=24d) Range of input is equal with the ratios of the output. You can find the pattern of output above 8,16,and 24 can divided by 8 and give the result 1,2 and 3
Is that good for you?
Good Luck!
<3

5 0

3 years ago

Determine the intercepts of the line. yy y y -intercept: (\Big( ( left parenthesis ,, , comma )\Big) ) right parenthesis xx x x

BlackZzzverrR [31]

Question:

Give all the x and y intercept of the function

$f(x) = \frac{3x^2 - 3x-60}{2x^3 + 2x^2-34x+30}$

Answer:

The x intercepts are x = 5 and x = -4

The y intercept is at y = -2

Step-by-step explanation:

Factorizing the numerator of the expression we find the x intercepts as follows;

$f(x) = \frac{3x^2 - 3x-60}{2x^3 + 2x^2-34x+30} =\frac{3(x-5)(x+4)}{2x^3 + 2x^2-34x+30}$

Therefore, the x intercept are

x = 5 and x = -4

To find the y intercept, we put x = 0 to get y = -2

Therefore, the y intercept is at y = -2

Factorizing the denominator we find the values for which the equation is undefined

2·x³ + 2·x² - 34·x + 30 = 2·(x-1)·(x-3)·(x+5) which gives

x = 1, 3 and -5.

4 0

3 years ago