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bulgar [2K]
3 years ago
5

A car is traveling at a rate of 81 kilometers per hour. What is the cars rate in kilometers per minute. How many kilometers will

the car travel in 15 minutes? Don't round
Mathematics
1 answer:
mario62 [17]3 years ago
8 0
If the car can travel 81 km in one hour, (60 minutes) that means that it can travel 81/60 in a minute. The result is 1.35, and this times 15 will give you the amount the car can travel in 15 minutes. The answer is 20.25km
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For which inequality is {x | x R, x > 6} the solution set?
CaHeK987 [17]

Answer:

C

Step-by-step explanation:

<em>B: 2X + 12 > 3</em>

2x > -9

x> -9/2

<em>C: 2X - 5 > 7</em>

2x > 12

x > 6

<em>D: 2x - 6 > 24</em>

2x > 30

x > 15

Hope this helps ^-^

6 0
3 years ago
1.905 rounded to the nearest tenth
Tema [17]
1.905 rounded to the nearest tenth is 1.9
4 0
3 years ago
Evaluate: -0.7 - (-2.6 + -0.8) + 7.1
SpyIntel [72]

Answer:

8.36

Step-by-step explanation:

-0.7-(-2.6+ -0.8) +7.1\\  (add inside the parenthesis)\\\\-0.7 - 3.4 + 7.1\\\\=8.36

3 0
3 years ago
The volume of a rectangular prism is given by the formula V = lwh, where / is the length of the prism, w is the width, and his
Vedmedyk [2.9K]
The answer would be option D.
10a^3 + 91a^2 + 54a - 792
6 0
3 years ago
2.A production process manufactures items with weights that are normally distributed with mean 10 pounds and standard deviation
Vesna [10]

Answer:

Step-by-step explanation:

Given that:

population mean = 10

standard deviation = 0.1

sample mean = 9.8 < x > 10.2

The z score can be computed as:

z = \dfrac{\bar x - \mu}{\sigma}

if x > 10.2

z = \dfrac{10.2- 10}{0.1}

z = \dfrac{0.2}{0.1}

z = 2

If x < 9.8

z = \dfrac{9.8- 10}{0.1}

z = \dfrac{-0.2}{0.1}

z = -2

The p-value = P (z ≤ 2) + P (z ≥ 2)

The p-value = P (z ≤ 2) + ( 1 -  P (z ≥ 2)

p-value = 0.022750 +(1 -   0.97725)

p-value = 0.022750 +  0.022750

p-value = 0.0455

Therefore; the probability of defectives  = 4.55%

the probability of acceptable = 1 - the probability of defectives

the probability of acceptable = 1 - 0.0455

the probability of acceptable = 0.9545

the probability of acceptable = 95.45%

4.55% are defective or 95.45% is acceptable.

sampling distribution of proportions:

sample size n=1000

p = 0.0455

The z - score for this distribution at most 5% of the items is;

z = \dfrac{0.05 - 0.0455}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}

z = \dfrac{0.0045}{\sqrt{\dfrac{0.04342975}{1000}}}

z = \dfrac{0.0045}{\sqrt{4.342975 \times 10^{-5}}}

z = 0.6828

The p-value = P(z ≤ 0.6828)

From the z tables

p-value = 0.7526

Thus, the probability that at most 5% of the items in a given batch will be defective = 0.7526

The z - score for this distribution for at least 85% of the items is;

z = \dfrac{0.85 - 0.9545}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}

z = \dfrac{-0.1045}{\sqrt{\dfrac{0.04342975}{1000}}}

z = −15.86

p-value = P(z ≥  -15.86)

p-value = 1 - P(z <  -15.86)

p-value = 1 - 0

p-value = 1

Thus, the probability that at least 85% of these items in a given batch will be acceptable = 1

6 0
3 years ago
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