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Harlamova29_29 [7]
2 years ago
13

Please help me I need help now

Mathematics
2 answers:
NemiM [27]2 years ago
5 0
Dividing by 10 is the same as moving the decimal point 1 place to the left.
Diano4ka-milaya [45]2 years ago
4 0
Answer is B one place to the left
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The equation for a hyperbola is (x-h)/a - (y-k)/b = 1
Or (y-k)/a - (x-h)/b = 1
h represents the x value of the coordinate
k value represents the y value of the coordinate 
together they represent a point, which is the center
So (h,k) is (x,y)

The asymptote is y-k = +/- b/a (x-h)
The transverse is the line that goes through the hyperbola. 
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3 years ago
Nine students Ryan’s class are wearing gray there are 30 students in his class Ryan says that 30% of his class is wearing gray i
aleksklad [387]

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Step-by-step explanation:

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3 years ago
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Which function is graphed below?<br><br>​
Masteriza [31]

Exponential Function.

y =  {a}^{x}  \:  \: (a > 0) \:  \: (a≠1)

Also the shown graph is a decreasing graph.

y =  {a}^{x}  \:  \: (0 < a < 1)

The equation above is the equation of the graph that is shown in the picture.

8 0
2 years ago
Helpppp plsssss!!thanks
DedPeter [7]
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2x - 6 - (3x + 9)
5 0
3 years ago
An open rectangular box having a volume of 108 in.3 is to be constructed from a tin sheet. Find the dimensions of such a box if
murzikaleks [220]

Answer:

6 in x 6 in x 3 in.

Step-by-step explanation:

Given

V = xyz = 108   ⇒   z = 108/(xy)

The amount of the material used is

S = xy + 2yz + 2xz

Put value of z from the volume

S = xy + 2y*108/(xy) + 2x*108/(xy) = xy + 216/x + 216/y

Now, we find the relative minimum of the function S(x,y)

First, we find the critical point. Set Sx = 0  and  Sy = 0

and solve this system:

Sx(x,y) = y - (216/x²) = 0

Sy(x,y) = x - (216/y²) = 0

From the first equation we have

y = 216/x²

Put it in the second equation and find x

x - (216/(216/x²)²) = 0

⇒  x*(1 - (x³/216)) = 0

⇒  x₁ = 0   and  x₂ = 6

Now, we can find y as follows

y₁ = 216/(0)²   which is undefined

y₂ = 216/(6)² = 6

Hence, the only critical point of S is (6, 6). Next, we calculate the second ordered derivatives that we need for the second derivative test:

Sxx(x,y) = 432/x³

Sxy(x,y) = 1

Syy(x,y) = 432/y³

Applying the second derivative test

D(6, 6) = Sxx(6, 6)*Syy(6, 6) - S²xy(6, 6) = 2*2 - 1² = 4 -1 = 3 > 0

Sxx(6, 6) = 2 > 0

Since D(6, 6) > 0   and   Sxx(6, 6) > 0   we can conclude that S has a relative minimum at (6, 6).

z coordinate is:

z = 108/(xy) = 108 / (6*6) = 3

Finally, the dimentions of a box are 6 in x 6 in x 3 in.

6 0
3 years ago
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