<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
There are several mutations that benefit the organism.A well known example is the antibiotic resistance developed by bacteria, which aid in their survival even when they are exposed to a given antibiotic. A single gene mutation in wild almond trees resulted in a variety that no longer synthesizes amygdalin.
Answer:
Dehydration is a concern since dehydration can lead to severe complications, such as seizures, swelling of the brain, kidney failure, shock, coma and even death. Signs and symptoms of dehydration include: Headache. Dizziness or lightheadedness.
Explanation:
Primary succession can occur in essentially lifeless areas or regions in which the soil is incapable of sustaining life as a result of such factors as lava, sand dunes, or rocks left from a retreating glacier.
Answer:
Aerobic respiration takes place in the mitochondria and requires oxygen and glucose, and produces carbon dioxide, water, and energy. ... Anaerobic respiration also produces energy and uses glucose, but it produces less energy and does not require oxygen.
Explanation:
