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Lostsunrise [7]
3 years ago
5

Rico and Darla each measured a side and height on the triangle below to find its area. Rico's side measured 7.5 m and Darla's si

de measured 9 m. Choose True or False for each statement. 1.Darla can use either the height of 6 meters or the height of 5 meters to find the area of the triangle. True or false? 2. If Darla uses the height of 6 meters and Rico uses the height of 5 meters, they will find the same area of the triangle. True or false? 3.If Rico uses the height of 6 meters and Darla uses the height of 5 meters, they will find the same area of the triangle. True or false? 4.The area of the triangle is 22.5 square meters. True or false?
Mathematics
1 answer:
polet [3.4K]3 years ago
7 0

Answer:

(1) True

(2) False

(3) True

(4) True

Step-by-step explanation:

(1) It is true Darla can use either the height of 6 m or 5 m to find the area of the triangle because Darla already knows the measurement of a side of the triangle. Multiplying the side by either of the heights divided by 2 gives the area of the triangle.

(2) It is false they will find the same area of the triangle.

Area of triangle = (side×height)/2

Darla's area of the triangle = (9×6)/2 = 54/2 = 27 m^2

Rico's area of the triangle = (7.5×5)/2 = 37.5/2 = 18.75 m^2

(3) It is true they will find the same area of the triangle.

Rico's area of the triangle = (7.5×6)/2 = 45/2 = 22.5 m^2

Darla's area of the triangle = (9×5)/2 = 45/2 = 22.5 m^2

(4) It is true the area of the triangle is 22.5 square meters as shown in part (3) above.

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A plane can fly 540 miles with the wind in one hour less than it can fly 480 miles against the wind. The average wind speed is 3
Bess [88]

Answer:

The speed of the plane in still air = 150 mph

Step-by-step explanation:

This is a relative velocity question

Let the velocity of the plane in still air be v

And let the time the plane can fly 480 miles against the wind be t

(Velocity of the plane relative to the wind) = (velocity of plane) - (velocity of wind)

Flying against the wind

(Velocity of plane relative to the wind) = (480/t)

(Velocity of the plane) = v

(Velocity of the wind) = 30 mph

(480/t) = v - 30

t = 480/(v-30) (eqn 1)

Flying with the wind

(Velocity of plane relative to the wind) = 540/(t-1)

(Velocity of the plane) = v

(Velocity of the wind) = -30 mph

540/(t - 1) = v + 30

t - 1 = 540/(v+30) (eqn 2)

Since t is equal in both cases, substitute the value of t in eqn 1 into eqn 2.

[480/(v-30)] - 1 = [540/(v+30)]

Multiply through by (v+30)(v-30)

480(v+30) - [(v+30)(v-30)] = 540(v-30)

480v + 14400 - (v² - 900) = 540v - 16200

480v + 14400 - v² + 900 = 540v - 16200

v² + 540v - 480v - 16200 - 14400 - 900 = 0

v² + 60v - 31500 = 0

Solving the quadratic equation,

v = 150 mph or v = -210 mph

We'll pick the positive answer because of the directions we have established.

Therefore, the speed of the plane in still air = 150 mph

Hope this Helps!!!

3 0
3 years ago
Write an equation for a parabola that has a vertex (1, 2) and passes through the point (3, -6).
Alex

Answer:

y= -2x²+4x.

Step-by-step explanation:

the common equation of the parabola is y=ax²+bx+c, where a, b, c - numbers.

1) the coordinates of the vertex are:

x_0=-\frac{b}{2a} \ and \ y_0=\frac{4ac-b^2}{4a}.

2) if according to the condition x₀=1, then b= -2a.

If according to the condition y₀=2, then   2=\frac{4ac-b^2}{4a}=\frac{4ac-4a^2}{4a}=c-a;

it means that c=a+2.

3) if b= -2a; c=a+2 and the point (3;-6) belongs to the given parabola, then it is possible to substitute them into the common equation of the parabola:

-6=3²*a-6a+a+2; ⇔ a= -2.

4) if a= -2, then b=-2a=4, and c=a+2=0.

5) if a=-2, b=4 and c=0, then the required equation of the parabola is:

y= -2x²+4x.

6 0
3 years ago
Jonathan has 1 3/4 hours to practice guitar. If he spends 1/8 hours on each song. How many songs can Jonathan practice? How many
blondinia [14]
This is my answer I think this will help you

6 0
3 years ago
FIRST TO ANSWER GETS BRALYIST<br> good luck :-)
Ratling [72]

Answer:

My answer is 20ft I'm not really sure but hope this helps

7 0
3 years ago
What is the equation of the line that passes through the point (8,-3) and has an undefined slope?
BARSIC [14]

Answer:

  x = 8

Step-by-step explanation:

A line with "undefined" slope is a vertical line, whose equation is of the form ...

  x = constant

In order for the line to go through a point with an x-coordinate of 8, the constant must be 8.

  x = 8 . . . . . a vertical line through (8, -3)

8 0
3 years ago
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