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Lina20 [59]
3 years ago
14

Nick walks 18,000 steps every day.

Mathematics
2 answers:
Alex787 [66]3 years ago
6 0
I believe he would average at least 1877 miles a year but my math may be incorrect.

elixir [45]3 years ago
5 0
(18000s/d)(365d/y)(mi/3500s)=1877.14 mi per year
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There are two jobs you can apply for. the first job pays $22,000 the first year, with raises of $4,000 each year thereafter. the
jasenka [17]
We let the number of years that the two jobs will have the same payment be denoted as t. Equating the wages of these two jobs after t - 1 years will give us an equation of,
                          22,000 + 4000(t -1) = 26,000 + 2000(t - 1)
The value of t from the generated equation is 3. Therefore, after 3 years the jobs will be paying the same wages.
7 0
3 years ago
Read 2 more answers
What is the factored form of x^2 -4x-12
denis-greek [22]

How about this?

(x - 6) x (x + 2)


8 0
3 years ago
20 points A rancher is planning the goat pen shown in the diagram. Determine the value of x, given that the rancher plans to use
4vir4ik [10]
I think i know what it is...
NOTTTTTTT
5 0
3 years ago
Guys I need help on all three please​
kodGreya [7K]

Answer:

graph 1 proportional

graph 2&3 is non proportional

i think

6 0
3 years ago
Use Gauss-Jordan elimination to solve the following linear system.
marysya [2.9K]
Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]
mulstiply 2nd row by -1 and add to 3rd
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]
divde last row by 2
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 2rd row by 6 and add to top one
\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 1st row by -1 and add to 2nd
\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]
divide 2nd row by -3
\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]
mulstiply 2nd row by -1 and add to 1st row
\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]
divide 1st row by -3
\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]

rerange
\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]

x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer
7 0
3 years ago
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