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3 years ago

How fast should the ant walk to go around the rectangle in 4 minutes?

Mathematics

1 answer:

vekshin13 years ago

4 0

Question:

How fast should the ant walk to go around the rectangle in 4 minutes if the sides are 12 inches and 16 inches

Answer:

The ant should walk 14 inches per minute

Solution:

Given that,

Dimensions of rectangle are 12 inches and 16 inches

Find the perimeter of rectangle

Perimeter = 2(length + width)

Perimeter = 2(12 + 16)

Perimeter = 2(28) = 56

Thus perimeter of rectangle is 56 inches

Time taken = 4 minutes

We have to find the speed at which ant covers 56 inches in 4 minutes

The speed is given by formula:

$speed = \frac{distance}{time}$

$speed = \frac{56}{4} = 14$

Thus the ant should walk 14 inches per minute

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Sum of two numbers is 38, one number is 36 more than the other. find the numbers

goldfiish [28.3K]

One number is 1 and the other one is 37. Coz u can make two variables x and y then make two functions x+y=38 and x-y=36 then solve it

3 0

3 years ago

A.Find the total and area of the compound figures

goldfiish [28.3K]

Answer:

(a) The total area of compound figure is $284.52ft^2$ .

(b) The total perimeter of compound figure is 68.84 ft.

Step-by-step explanation:

Perimeter: The total distance covered by the figure.

Area: It is defined as the space occupied by the figure.

Given:

Length of rectangular figure = 19 ft

Breadth of rectangular figure = 12 ft

Radius of circle, r = $\frac{12ft}{2} = 6 ft$

Part (a):

Now calculating the total area of the compound figure.

$\text{Total area}=\text{Area of rectangular figure}+\frac{1}{2}\times \text{Area of circle}\\\\\text{Total area}=\text{Length}\times \text{Breadth}+\frac{1}{2}\times \pi r^2$

Now putting all the given values in this formula, we get:

$\text{Total area}=(19ft\times 12ft)+\frac{1}{2}\times 3.14\times (6ft)^2\\\\\text{Total area}=284.52ft^2$

Part (b):

Now calculating the total perimeter of the compound figure.

$\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times \text{Circumference})\\\\\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times 2\times \pi \times r)$

Now putting all the given values in this formula, we get:

$\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times 2\times \pi \times r)\\\\\text{Total perimeter}=2\times 19ft+12ft+(\frac{1}{2}\times 2\times 3.14 \times 6ft)\\\\\text{Total perimeter}=68.84ft$

8 0

3 years ago

Please help it's due today!!!!!!

BlackZzzverrR [31]

Answer:

See Below

Step-by-step explanation:

We are given 3 equations.

3x + 8

5x - 20

and

5x + 4y

First lets solve for x using the first two

3x + 8 = 5x -20

Move the variables to one side

3x + 8 = 5x -20

-3x -3x

8 = 2x -20

+20 +20

28 =2x

28/2 =2x /2

14 = x

Now we have x = 14

Lets plug this into the second equation to solve for the angle

3(14) + 8

42 + 8 = 50

5(14) - 20

70 - 20 =50

Now, lets plug the x and the angle into the third equation to find y

5 (14) +4y = 50

70 + 4y = 50

-70 -70

4y = -20

4y/4 = -20/4

y = -5

So now we have:

x = 14

y = -5

and the angle = 50

Hope this helps!

6 0

4 years ago

Please help asap, this is timed!!!!!! I'll mark brainliest!

Leto [7]

Hi! i think it’s d, just by process of elimination!! it cant be any of the others, and d estimates to be right.

4 0

3 years ago

Find The art length of a sector with an area of 8 square units.

frez [133]

$\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta \pi r^2}{360}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
A=8\\
r=4
\end{cases}\implies 8=\cfrac{\theta \pi 4^2}{360}\implies \cfrac{8\cdot 360}{4^2\pi }=\theta 
\\\\\\
\cfrac{2880}{16\pi }=\theta \implies \boxed{\cfrac{180}{\pi }=\theta }\\\\
-------------------------------\\\\$

$\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
\theta =\frac{180}{\pi }\\
r=4
\end{cases}\implies s=\cfrac{\frac{180}{\underline{\pi} }\underline{\pi} \cdot 4}{180}\implies s=\cfrac{\underline{180}\cdot 4}{\underline{180}}
\\\\\\
\boxed{s=4}$

if you do a quick calculation on what that angle is, you'll notice that it is exactly 1 radian, and an angle of 1 radian, has an arc that is the same length as its radius.

that's pretty much what one-radian stands for, an angle, whose arc is the same length as its radius.

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3 years ago