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Leto [7]
4 years ago
10

What's the unit rate for 640 miles in 25 hours

Mathematics
1 answer:
Viktor [21]4 years ago
8 0
I think it would be 25.6 miles per hour

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What is 5 3/5% of 750?<br><br> Thanks in advance.
GREYUIT [131]
<h3>given:</h3>

5 \frac{3}{5} \% \: of \: 750

<h3>solution:</h3>

5 \frac{3}{5}  = 5.6

\frac{5.6\%}{100}  \times  \frac{x}{750}

= 42%

6 0
2 years ago
Find the area of the shaded region
kodGreya [7K]

Answer:  21.994 cm²

Step-by-step explanation:

Area of the shaded region = Area of the bigger circle - the areas of the two smaller circles.

Formula for finding area of a circle       =  πr² where π is a constants . It has value of         22/7 or 3.142

Now area of the bigger circle                = 3.142 x 3²

                                                                  = 3.142 x 9

                                                                  = 28.278 cm²                                       Now are of the two smaller triangle        = 3.142 x 1² x 2

                                                                   = 6.284 cm².

Therefore are of the shaded region        = 28.278 - 6.284

                                                                   = 21.994 cm²

7 0
3 years ago
What is the graph represents the equation y=1/3x+2
Kaylis [27]

Step-by-step explanation:

step 1. you mean which graph represents the equation y = (1/3)x + 2?

step 2. please provide the graphs - they are missing.

step 3. the equation has a slope of 1/3 which means it goes up one and three to the right.

step 4. the y intercept is 2 so it goes through the point (0, 2).

3 0
3 years ago
Coach ramirez bought 8 cases of bottled water for a road race. There are 24 bottles in each case. After the race, 34 bottles of
navik [9.2K]

158 bottles of water were used at the race

3 0
3 years ago
Can someone help me with this​
SashulF [63]

Answer:

\angle NRQ =85 \degree

Given:

\angle RPQ = 45 \degree \\  \angle PQR = (6x + 4)\degree \\  \angle NRQ = (15x - 5)\degree

Step-by-step explanation:

Property used: <em>An exterior angle of a triangle is equal to the sum of the opposite int</em><em>e</em><em>rior angles.</em>

<em>=  >  \angle RPQ +  \angle PQR =  \angle NRQ \\  \\  =  > 45 \degree + (6x + 4)\degree = (15x - 5)\degree \\  \\  =  > 45\degree + 6x\degree + 4\degree = 15x\degree - 5\degree \\  \\  =  > 49\degree  + 5 \degree= 15x\degree - 6x\degree \\  \\  =  > 54\degree = 9x\degree \\  \\  =  > 9x\degree = 54\degree \\  \\  =  > x\degree =  (\frac{54}{9} )\degree \\  \\  =  > x\degree = 6\degree \\  \\ Putting \: value \: of \: x \: in \:  \angle NRQ  \\   \\  =  > \angle NRQ = (15x - 5)\degree \\  \\  =  >  \angle NRQ = (15 \times 6 - 5) \degree \\  \\  =  >  \angle NRQ =85 \degree</em>

4 0
3 years ago
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