Answer:
(a) Hence, the probability of reporting heads is 1/2.
(b) Therefore, the expected number of such trial is 1 / 2p (1 –p).
Step-by-step explanation:
Solution:
To generate a random variable takes value 0 and 1.
Let 0 < p <1,
A coin is flipped twice.
(a) Probability of reporting head is 1/2.
The result of two toss is either HT or TH.
In this case we used conditional property, Given that you got either HT or TH,
Probability of occurring head or tail:
P (1ST = H| HT or TH]
= P (H) / P (HT or TH)
= P (HT) / P (HT or TH)
= P (1-P) / P (1-P) + (1-P)P
= P (1-P) / 2P (1-P)
=1/2
Hence, the probability of reporting heads is 1/2.
(b) Expected number of flip before report a result.
The probability of reporting a result on each trial is:
P (HT or TH)
=P (HT) + P (TH)
=P (1-P) + (1 –P) P
= 2P (1 –P)
Since, E(X) = 1 / P
Therefore, the expected number of such trial is 1 / 2p (1 –p).
