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3 years ago

2/3 divided by 1/12 on number line

Mathematics

1 answer:

allsm [11]3 years ago

6 0

Answer:

.05

Step-by-step explanation:

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HELP I GIVE BRAINLIEST:)

V125BC [204]

Answer:

A. 7/9

Step-by-step explanation:

8 0

3 years ago

Price of 1kg sugar is Rs. 100 calculate the price of 150g sugar?

Wewaii [24]

Answer:Rs15

Step-by-step explanation:

150g=150/1000=0.15kg

1kg cost Rs100

0.15kg cost =100 x 0.15=15

150g cost Rs15

3 0

3 years ago

Tamara and Amir shared a candy bar. Tamara ate two fifths. Amir ate two fifths. How much is left?

marin [14]

Answer:

1/5

Step-by-step explanation:

Both Amir and Tamara ate 2/5 each.

2/5 + 2/5 = 4/5

If 4/5 of the candy bar was eaten, 1/5 of the candy bar remains because

5/5 - 4/5 = 1/5

(Remember that 5/5 just equals one whole, representing the whole candy bar)

7 0

3 years ago

For ssc

Inga [223]

Answer:

Average speed is 3 kilometers an hour

4 0

2 years ago

Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap

pantera1 [17]

Answer:

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e $\dfrac{dV}{dt}= 20 \ ft^3/min$

we know that radius r is always twice the diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

$V = \dfrac{\pi r^2 h}{3}$

$V = \dfrac{\pi (h/2)^2 h}{3}$

$V = \dfrac{1}{12} \pi h^3$

$V = \dfrac{ \pi h^3}{12}$

Taking the differentiation of volume V with respect to time t; we have:

$\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}$

$\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}$

we know that:

$\dfrac{dV}{dt}= 20 \ ft^3/min$

So;we have:

$20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}$

$20= 56.25 \pi \times \dfrac{dh}{dt}$

$\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

8 0

3 years ago