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yKpoI14uk [10]
2 years ago
13

If anyone could help also step by step please with work

Mathematics
1 answer:
Rasek [7]2 years ago
6 0

9514 1404 393

Answer:

  m = 1/3

Step-by-step explanation:

<u>Step 1</u>. Pick a line of the table to use as (x1, y1).

<u>Step 2</u>. Pick a different line of the table to use as (x2, y2).

<u>Step 3</u>. Use the slope formula:

  m = (y2 -y1)/(x2 -x1)

<u>Step 4</u>. Simplify the result.

__

Here are these steps for this problem.

1, 2. use (x1, y1) = (-9, -5) and (x2, y2) = (-3, -3)

3. m = (-3 -(-5))/(-3 -(-9)) = 2/6

4. m = 1/3

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Alexxandr [17]

It should just be 2y. Hope it helps.



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Daniel's is correct

Step-by-step explanation:

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i need to find an equation for this problem that applies to any step (e.g. step 100) but my brain doesn't work
Anton [14]

Answer:

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Step-by-step explanation:

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A study was conducted to determine whether there were significant differences between medical students admitted through special
BabaBlast [244]

Answer:

A) 0.7696

B) 0.0474

C) Yes it's unusual

D) 0.05746

E) No, it is not unusual

F) No, it is not unusual

Step-by-step explanation:

This is a binomial probability distribution question.

We are told that 92.4% of those admitted graduated.

Thus; p = 92.4% = 0.924

From binomial probability distribution, q = 1 - p

Thus;

q = 1 - 0.924

q = 0.076

Formula for binomial probability distribution is;

P(x) = nCx × p^(x) × q^(n - x)

A) At least 11 graduated out of 12.

P(x ≥ 11) = P(11) + P(12)

P(11) = 12C11 × 0.924^(11) × 0.076^(12 - 11)

P(11) = 0.3823

P(12) = 12C12 × 0.924^(12) × 0.076^(12 - 12)

P(12) = 0.3873

P(x ≥ 11) = 0.3823 + 0.3873

P(x ≥ 11) = 0.7696

B) that exactly 9 of them graduated out of 12. This is;

P(9) = 12C9 × 0.924^(9) × 0.076^(12 - 9)

P(9) = 0.0474

C) We are not given significance level here but generally when not given we adopt a significance level of α = 0.05.

Now, exactly 9 out of 12 that graduated which is P(9) = 0.0474.

We see that 0.0474 is less than the significance level of 0.05. Thus, we can say that it is unusual to randomly select 12 students from the special programs and get exactly 9 that graduate

D) that at most 9 of them out of 12 graduated.

P(x ≤ 9) = P(0) + P(1) + P(2) + P(3) + P(4) + P(5) + P(6) + P(7) + P(8) + P(9)

This is going to be very long so I will make use of an online probability calculator to get the values of P(0) to P(8) since I already have P(9) as 0.0474.

Thus, we have;

P(0) = 0

P(1) = 0

P(2) = 0

P(3) = 0.00000001468

P(4) = 0.00000040161

P(5) = 0.00000781232

P(6) = 0.00011081163

P(7) = 0.00115477385

P(8) = 0.00877476184

Thus;

P(x ≤ 9) = 0 + 0 + 0 + 0.00000001468 + 0.00000040161 + 0.00000781232 + 0.00011081163 + 0.00115477385 + 0.00877476184 + 0.04741450256

P(x ≤ 9) = 0.05746

E) P(x ≤ 9) = 0.05746 is more than the significance level of 0.05, thus we will say it is not unusual.

F) from online binomial probability calculator, probability of getting only 9 out of 12 is more than the significance value of 0.05. Thus, we will say it is not unusual

7 0
3 years ago
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snow_lady [41]

I think it's histograms for the first blank; distribution for the second blank; frequency for the third and final blank.

Hope this helps please let me know if I'm wrong :)))

8 0
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