The way to determine the number of solutions is to complete the problem in multiple different ways.
Hey there!
Let's create a systems of equations using x and y.
4x+3y=15
3x-2y=7
We need to solve this using elimination. First, we need to multiply the first equation by 2/3 so that we can cancel out the y's when combining our equations.
2 2/3x+2y=10
3x-2y=7
Now we combine the equations...
5 2/3x=17
x=3
Now we can plug our x into the first equation to find y.
12+3y=15
y=1
Our numbers are 3 and 1.
I hope this helps!
Uhhh that doesn’t seem possible but then again i forgot simple math lol
<span>Each number had 10 possibilities. So to calculate the number of possibilities for two numbers multiply 10 by 10. This means that for all 4 digits the number of possible permutations is 10x10x10x10 or 10 to the power 4. This equals to 10,000 therefore D.
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Answer:
1/3
Step-by-step explanation:
