All categories

2 years ago

Nick has a box of ornaments that he uses to

Mathematics

1 answer:

Lelu [443]2 years ago

7 0

Answer:

Step-by-step explanation:

6 + 6 + 6 = 18

If this helps, please give me branliest! I need it.

You might be interested in

What is the slope of the line represented by the equation 10×+5y=4<br>a.2<br>b.1/2<br>c.-1/2<br>d.-2

VikaD [51]

Equation: 10x + 5y = 4
5y = -10x + 4

Divide the equation by 5,
y = -2x + 4/5

Now Compare it with, y = mx + c
Here,m = -2

In short, Your Answer would be Option D

Hope this helps!

6 0

3 years ago

Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips. Urn II contains three red

Neporo4naja [7]

Answer:

Multiple answers

Step-by-step explanation:

The original urns have:

Urn 1 = 2 red + 4 white = 6 chips
Urn 2 = 3 red + 1 white = 4 chips

We take one chip from the first urn, so we have:

The probability of take a red one is : $\frac{1}{3}$ (2 red from 6 chips(2/6=1/2))

For a white one is: $\frac{2}{3}$ (4 white from 6 chips(4/6=(2/3))

Then we put this chip into the second urn:

We have two possible cases:

First if the chip we got from the first urn was white. The urn 2 now has 3 red + 2 whites = 5 chips
Second if the chip we got from the first urn was red. The urn two now has 4 red + 1 white = 5 chips

If we select a chip from the urn two:

In the first case the probability of taking a white one is of: $\frac{2}{5}$ = 40% ( 2 whites of 5 chips)
In the second case the probability of taking a white one is of: $\frac{1}{5}$ = 20% ( 1 whites of 5 chips)

This problem is a dependent event because the final result depends of the first chip we got from the urn 1.

For the fist case we multiply :

$\frac{4}{6}$ x $\frac{2}{5}$ = $\frac{4}{15}$ = 26.66% ( $\frac{4}{6}$ the probability of taking a white chip from the urn 1, $\frac{2}{5}$ the probability of taking a white chip from urn two)

For the second case we multiply:

$\frac{1}{3}$ x $\frac{1}{5}$ = $\frac{1}{30}$ = .06% ( $\frac{1}{3}$ the probability of taking a red chip from the urn 1, $\frac{1}{5}$ the probability of taking a white chip from the urn two)

8 0

3 years ago

An archaeologist at a dig sets up a coordinate system using string. Two similar artifacts are found one at position (1, 4) and t

myrzilka [38]

Given:

Positions of two artifacts are at points (1, 4) and (5, 2).

To find:

The distance between these two artifacts.

Solution:

Distance formula: The distance between two points is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, the distance between two points (1, 4) and (5, 2) is

$d=\sqrt{(5-1)^2+(2-4)^2}$

$d=\sqrt{(4)^2+(-2)^2}$

$d=\sqrt{16+4}$

$d=\sqrt{20}$

$d=4.4721359$

Round to the nearest tenth of a unit.

$d\approx 4.5$

Therefore, the distance between two artifacts is 4.5 units.

4 0

2 years ago

F(x)=-9x^2-2x and g(x)=-3x^2+6x-9, find (f-g)(x) and (f-g)(-4)

Alona [7]

Answer:

(f - g)(x)= - 6 {x}^{2} - 8x + 9

(f - g)(-4!)= - 55

Step-by-step explanation:

$f(x) = - 9 {x}^{2} - 2x, \: \: g(x) = - 3 {x}^{2} + 6x - 9 \\ (f - g)(x) = f(x) - g(x) \\ = - 9 {x}^{2} - 2x - (- 3 {x}^{2} + 6x - 9) \\ = - 9 {x}^{2} - 2x + 3 {x}^{2} - 6x + 9 \\ \purple{ \boxed{ \bold{(f - g)(x)= - 6 {x}^{2} - 8x + 9}}} \\ (f - g)( - 4)= - 6 {( -4 )}^{2} - 8( - 4) + 9 \\ = - 6 \times 16 + 32 + 9 \\ = - 96 + 41 \\ \red{ \boxed{ \bold{(f - g)( - 4)= - 55}}}$

6 0

2 years ago

I need help with answering the following questions. :/ :)

s344n2d4d5 [400]

Answer:

a) (0, ∞)

b) (-∞, ∞)

c) x = 0

Step-by-step explanation:

It helps to have some idea what the log function is.

a) The domain is all positive numbers: (0, ∞).

b) The range is all real numbers: (-∞, ∞). (The vertical translation downward by 5 units does not change that.)

c) There is a vertical asymptote where the argument of the log function is zero: at x=0.

3 0

3 years ago