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2 years ago

Solve the following problems. Choose the letter of the correct answer. (Show your complete solutions.)

Mathematics

1 answer:

motikmotik2 years ago

6 0

i didnt understand the question because of my English sorry

we all know that the total of degrees is 180 so 70+70=140

180-140=40

so the answer is 40

we have a figure with 4 angle so the total of degrees is 360 so the answer is 126

the answer most be 50 becuse we have a Special degree witch always equal 90 if we have recatngle so

x+40=90

X=50 the answer and if you want to try again choose the second one

2x-10=90

2x=100

X=50 same answe you see

in this quastion i searched and find alot of answers any way

its should be 7 or 3 but the correct answer in my opinion its 7

its shows in the picture i sent hopefully its helpful to you i will try to translate the first quastion and sent it to you

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What are the solutions to log (x² + 8) = 1 +logo(x)?

kherson [118]

Answer:

x = 9.125 and 0.875

Step-by-step explanation:

Given the expression

log (x² + 8) = 1 +log(x)?

This can also be written as;

log (x² + 8) = log 10 +logo(x)

log (x² + 8) = log(10x)

(x² + 8) = (10x)

x² -10x + 8 = 0

Factorize;

x = 10±√(-10)²-4(8)/2

x = 10±√100-32/2

x = 10±√68/2

x = 10±8.25/2

x = 10+8.25/2 and 10-8.25/2

x = 18.25/2 and 1.75/2

x = 9.125 and 0.875

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3 years ago

Calculate CDEFtrapezium

pantera1 [17]

｡☆✼★ ━━━━━━━━━━━━━━ ☾

You need to find the length of A F and BC first

Lets call BC --> 'x'

Lets form an equation

9 + 9 + x + x = 28

18 + 2x = 28

- 18

2x = 10

/ 2

x = 5

So now we have the length BC

We can subtract this length from the 11cm to find the vertical height of the trapezium

11 - 5 = 6

Now we have all we need to work it out.

area = (a + b) / 2 x h

area = (5 + 9) / 2 x 6

area = 42 cm^2

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5 0

3 years ago

Read 2 more answers

Factor completely. 3x^2-3x-18 HINT: Factor out the greatest common factor first.

lubasha [3.4K]

Answer:

3(x - 3)(x + 2)

Step-by-step explanation:

take out a common factor of 3 from each term

= 3(x² - x - 6)

to factor the quadratic consider the factors of - 6 which sum to - 1

These are - 3 and + 2, hence

3x² - 3x - 18 = 3(x - 3)(x + 2) ← in factored form

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3 years ago

I dO nOt coMprEheNd PLEASE HELPPP

jasenka [17]

Lines y=-x+2 and y=3x+1 intersect the y=axis. If you plot them out on a graph using the equation y=mx+b, then they are parallel and are set on the y-axis.

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3 years ago

In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank

fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) $Amount \ of \, water \ remaining \ in \, the \ tank \ is \ \frac{x^3(6-\pi) }{6}$

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The volume of the sphere = $\frac{4}{3} \pi r^3$

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = $\frac{4}{3} \pi \frac{x^3}{8}$ = $\frac{1}{6} \pi x^3$

For tank B

Volume of tank = x³

The volume of the spheres = $8 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = $8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}$

For tank C

Volume of tank = x³

The volume of the spheres = $64 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = $64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}$

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The volume of the spheres = $512 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = $512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}$

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = $x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}$

$Amount \ of \ water \, remaining \, in \, the \ tank = \frac{x^3(6-\pi) }{6}$ .

5 0

3 years ago