The sixth term of an arithmetic sequence is 6
<h3>How to find arithmetic sequence?</h3>
The sum of the first four terms of an arithmetic sequence is 10.
The fifth term is 5.
Therefore,
sum of term = n / 2(2a + (n - 1)d)
where
- a = first term
- d = common difference
- n = number of terms
Therefore,
n = 4
10 = 4 / 2 (2a + 3d)
10 = 2(2a + 3d)
10 = 4a + 6d
4a + 6d = 10
a + 4d = 5
4a + 6d = 10
4a + 16d = 20
10d = 10
d = 1
a + 4(1) = 5
a = 1
Therefore,
6th term = a + 5d
6th term = 1 + 5(1)
6th term = 6
learn more on sequence here: brainly.com/question/24128922
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Answer:
nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine
Step-by-step explanation:
we know that
The <u><em>Power of a Power Property</em></u>
, states that :To find a power of a power, multiply the exponents
so

In this problem we have
![9^{\frac{1}{3}} =\sqrt[3]{9}](https://tex.z-dn.net/?f=9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%3D%5Csqrt%5B3%5D%7B9%7D)
Remember that
![\sqrt[3]{9}=9^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7D%3D9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
Raise to the third power
![[9^{\frac{1}{3}}]^3](https://tex.z-dn.net/?f=%5B9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5D%5E3)
Applying the power of power property



therefore
nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine
Solve for p by simplifying both sides of the equation, then isolating the variable.
p= - 7/3