Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.
Use cosine.
We have:
adjacent = 9cm and hypotenuse = 17 cm
Answer:
Hi there! Your answer here is 11kg - the average of the seven weights is 11kg. To find the average of a group of numbers, you add all of the numbers (12, 12, 12, 12, 12, 12, 5), then divide by the count of those numbers (7).
12 + 12 + 12 + 12 + 12 + 12 + 5 (or 12*6 + 5) is equal to 77.
77 / 7 = 11.
So the average of the seven weights is 11kg.
Have a great day! - Mani :)
Answer:
$690.86
Step-by-step explanation:
100% from the original cost is: 2 x 863.57 = $1,727.14
40/100 = X/1727.14 (40 percent is what of 1,727.40) (%/100 = is/of)
(40 * 1,727.14) / 100 = $ 690.86
74/100=34/n
cross multiply proportion
74n=3400
then divide both sides by 74
n= ~46
