Answer:
True
Step-by-step explanation:
Think about it. you are cutting a rectangle in half. and when you put it in dimensions its still the same thing!
Answer:
Step-by-step explanation:
R(0,0)
A=((0+2a)/2,(0+2b)/2)=(a,b)
S(2a,2b)
B=((2a+2c)/2,(2b+2d)/2)=(a+c,b+d)
T(2c,2d)
C=((2c+2c)/2,(2d+0)/2)=(2c,d)
V(2c,0)
D=((2c+0)/2,(0+0)/2)=(c,0)
R(0,0)
slope of AB=(b+d-b)/(a+c-a)=d/c
slope of DC=(d-0)/(2c-c)=d/c
slope of AD=(0-b)/(c-a)=-b/(c-a)
slope of BC=(d-b-d)/(2c-a-c)=-b/(c-a)
I wouldn't use the phrase "extends from." If the leading coeff. is neg, then the graph opens downward. Without more info we do not know the max of this fn. If we did know it, we could state that the graph max is (value) and that the graph "extends downward from this value."
Answer:
I think it would be C
Step-by-step explanation:
Answer:
450
Step-by-step explanation:
