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STALIN [3.7K]
2 years ago
8

The average of six weights is 12 kilograms. Another weight of 5 kilograms is added to the scale. What is the average of the seve

n weights?
Mathematics
1 answer:
Anastaziya [24]2 years ago
5 0

Answer:

Hi there! Your answer here is 11kg - the average of the seven weights is 11kg. To find the average of a group of numbers, you add all of the numbers (12, 12, 12, 12, 12, 12, 5), then divide by the count of those numbers (7).

12 + 12 + 12 + 12 + 12 + 12 + 5 (or 12*6 + 5) is equal to 77.

77 / 7 = 11.

So the average of the seven weights is 11kg.

Have a great day! - Mani :)

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The following are scores for students in Ms. Kennedy's math class.What is the range of the scores?
Eddi Din [679]

Answer:

The answer will be D. 181

Step-by-step explanation:

603 - 422 = 181

<em>Please mark me as the brainliest.</em>

3 0
2 years ago
In a right triangle the two sides are 10 and 5. find all possible values for the third side.
nikitadnepr [17]

Answer:

1. about 11.18

2. about 8.66

Step-by-step explanation:

1. 5^2 + 10^2= 125

square root of 125 equals about 11.18

2. 10^2-5^2=75

square root of 75 equals about 8.66

7 0
3 years ago
Evaluate the triple integral.
Irina-Kira [14]

The definition of the set E gives you a natural choice for the limits in the integral:

\displaystyle \iiint_E y \, dV = \int_0^6 \int_0^x \int_{x-y}^{x+y} y \, dz \, dy \, dx

Computing the integral, we get

\displaystyle \iiint_E y \, dV = \int_0^6 \int_0^x y ((x+y)-(x-y)) \, dy \, dx = 2 \int_0^6 \int_0^x y^2 \, dy \, dx

\displaystyle \iiint_E y \, dV = 2 \int_0^6 \frac13 (x^3 - 0^3) \, dx = \frac23 \int_0^6 x^3 \, dx

\displaystyle \iiint_E y \, dV = \frac23 \cdot \frac14 (6^4 - 0^4) = \boxed{216}

6 0
2 years ago
Yesterday Bethany sent 60 text messages she said that 15% of those messages were to her best friend how many text messages didn'
V125BC [204]

Answer:

51 messages

Step-by-step explanation:

15% of 60

15*60 = 900

900/100 = 9

and now 60-9 = 51

Final answer: She didnt sent 51 messages to her friend

4 0
3 years ago
Write 1 over 9 as a decimal and round it to 2 decimal places
FromTheMoon [43]

Answer:

0.111

Step-by-step explanation:

1/9 as a decimal is 0.11111111 but rounded to 2 decimal places is 0.111.

Hope this helps :)

Have a good day / night

3 0
2 years ago
Read 2 more answers
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