Answer:
-6re−r [sin(6θ) - cos(6θ)]
Step-by-step explanation:
the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ
x = e−r sin(6θ), y = er cos(6θ)
δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)
δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)
∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ
= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]
= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))
= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]
= -6re−r [sin(6θ) - cos(6θ)] since [cos²(6θ) + sin²(6θ)] = 1
If you graph it, it looks linear.
Answer:
-14/5
Step-by-step explanation:
+ - you have to remove the plus sign so it just becomes -
then you get,
-11/5 - 3/5 = -14/5
Answer:
1. CYNARG
Step-by-step explanation:
This a example of Caesar's Cipher, in which each letter in the original word leads to a ciphered letter according to the following equation:

In which C is the index of the Ciphered letter in the alphabet, P is the index of the original letter and o is the offset.
Finding the offset:
O is coded B
O is the 15th letter in the alphabet, so
.
B is the 2nd letter in the alphabet, so 




So

PLANET:
P
P is the 16th letter in the alphabet.

So P is coded C.
L
L is the 12th letter in the alphabet:

L is coded Y(25th letter in the alphabet)
A
A is the 1st letter in the alphabet

A is coded N
N
N is the 14th letter in the alphabet

N is coded A
E
E is the 5th letter in the alphabet

E is coded R
So the correct answer is:
1. CYNARG
Answer:
ASSOCIATIVE PROPERTY OF MULTIPLICATION
Step-by-step explanation:
HOPE IT HELPS
HAVE A GREAT DAY