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maw [93]
3 years ago
13

charlie had a circular patio with a radius of 6 feet. the radius is 12 bricks in length. how many bricks would be in the diamete

r of the patio?
Mathematics
1 answer:
alex41 [277]3 years ago
7 0

Answer:

24 Bricks.

Step-by-step explanation:

We know the radius is 6 feet and that the diameter is twice that.

We also know the radius is 12 'bricks' in length.

If we divide both numbers by 12, we get that 1 'brick' is half a foot.

Since that's the radius and we want the diameter, we multiply the radius by 2 to get the diameter.

This results in 12 feet, or 24 'bricks'.

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A restaurant buys 56 pounds of beef at $1.12/pound and 24 quarts of milk at $.90/quart. How much money was spent?
Gre4nikov [31]

Answer:

84.80

Step-by-step explanation: 62.72+22.08=84.80

3 0
3 years ago
Read 2 more answers
Convert (10111)2 into decimal number system​
Eva8 [605]

Answer:

(10111)_2 = (23)_{10}

Step-by-step explanation:

(10111)_2 = (1 \times 2^4) + (0 \times 2 ^3) + (1 \times 2^2) + (1 \times 2) + (1 \times 2^0)

            = 16 + 0 + 4 + 2 + 1\\=23

4 0
2 years ago
When Brad was born, his Grandma put, $1,500 in a new account for him. Since then, the balance of the account, has grown by 6.5%
marin [14]

Answer:

$969.04

Step-by-step explanation:

now at age of 18 Brad has 1500 * 1,065^18

at age of 21 he will have 1500 * 1,065^21

if he waits the difference will be 1500 * 1,065^21 - 1500 * 1,065^18 = $969.04

6 0
3 years ago
What is the sum of the first 70 consecutive odd numbers? Explain.
expeople1 [14]

The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.

Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.

So, if we sum the first N odd numbers, we have

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1

The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have

\displaystyle 2\sum_{i=1}^N i = 2\cdot\dfrac{N(N+1)}{2}=N(N+1)

The second sum is simply the sum of N ones:

\underbrace{1+1+1\ldots+1}_{N\text{ times}}=N

So, the final result is

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1 = N(N+1)-N = N^2+N-N = N^2

which ends the proof.

5 0
2 years ago
Find <br> 2 numbers greater than 6 with the LCM 40
Katarina [22]
That is impossible but I did some math so there are 2 ways that will equal more than 40.

6.7×6.0=40.2
6.5×6.2=40.3

Hope this helps!
6 0
3 years ago
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