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Hatshy [7]
3 years ago
6

Complete the equation of the line through (6,-6) and (8,8)

Mathematics
1 answer:
melomori [17]3 years ago
3 0
General formula to determine the equation of the line
y - y₁ = m(x - x₁)
(x₁,y₁) is one of the points which lies n the line
m represents the slope

Find the slope
Given:
(x₁,y₁) = (6,-6)
(x₂,y₂) = (8,8)

We could find the slope by using this formula
m = \dfrac{ y_{2} -y_{1} }{ x_{2} -x_{1} }

Plug in the numbers
m = \dfrac{ y_{2} -y_{1} }{ x_{2} -x_{1} }
m = \dfrac{8-(-6)}{8-6}
m = \dfrac{14}{ 2 }
m = 7
The slope is 7

Determine the line equation
Plug one of the points (you could choose any of points given from the question) and the slope to the formula of line equation
y - y₁ = m(x - x₁)
y - (-6) = 7(x - 6)
y + 6 = 7x - 42
y = 7x - 42 - 6
y = 7x - 48
<em>This is the equation of the line</em>
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The length of a bridge is 190 m. The length of each of Robert's paces is 80 cm.
ohaa [14]

Answer:

Step-by-step explanation:

Length of the bridge = 190 m = 190*100 = 19000 cm    {100cm = 1m}

Length of each pace of Robert = 80 cm

Minimum number of full paces = 19000/80

=  237.5

= 238   {because full paces}

5 0
3 years ago
Read 2 more answers
SOMEONE HELP ME WITH THIS ONE PLZ!
kolezko [41]
To construct a circle that circumscribes to a triangle, you would have to construct a circle that where all vertices of the triangle are on the circle. To do this you would have to construct the perpendicular bisectors of each side with your compass and straight edge. Comment on this answer if you are unsure of how to construct a perpendicular bisect (it's a long fundamental process to describe, and I wouldn't want to lecture you one something you already know). Once you have done so, set your compass point on the point where all perpendicular bisectors intersect (they should intersect in ONE point, if not you will have to redo it). Set your other compass lead on one of the vertices and spin away! If you have done this correctly, you should hit all three vertices when spinning your compass. Hope this helps!

Fun fact: the point where all perpendicular bisectors intersect is called the circumcenter
3 0
3 years ago
Please help.. part a &amp; b
umka21 [38]

Answer:

Part A

to the 10th power will be positive and to the 11th power is negative. When the exponent is even it will be positive. When it is odd it will be negative

Part B

The one with the negative enclosed will be positive. The second one, the exponent is only effecting the number and not the sign. The outcome will always be negative.

4 0
3 years ago
What are the solutions to x2 + 8x + 7 = 0?
nikitadnepr [17]

Answer:

x= -1 and x= -7

hope it helps.

5 0
3 years ago
The largest set of x values satisfying
velikii [3]

Answer:

If p\ge -\dfrac{1}{3}, then x>\dfrac{2}{3}+p and mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p

Step-by-step explanation:

Solve two inequalities for x.

1. 2,018x-p

Separate terms with x and without x into two sides:

2,018x-2,020x

Multiply by -1:

2x>-2p\\ \\x>-p

2. 7x+3p

Separate terms with x and without x into two sides:

7x-10x

Multiply by -1:

3x>2+3p\\ \\x>\dfrac{2}{3}+p

Find the largest set of x values satisfying both inequalities:

x>-p\\ \\x>\dfrac{2}{3}+p

If

-p>\dfrac{2}{3}+p\\ \\-2p>\dfrac{2}{3}\\ \\2p

then x>-p and mn=-p=p\cdot (-1),\ m+n=p-1. In this case both m and n are negative.

If p>-\dfrac{1}{3}, then x>\dfrac{2}{3}+p and mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p

If p=-\dfrac{1}{3}, then x>\dfrac{1}{3} and mn=\dfrac{1}{3}=\dfrac{1}{3}\cdot 1,\ \ m+n=\dfrac{4}{3}

7 0
3 years ago
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