Answer:
School Sucks!
Step-by-step explanation:
Half of this stuff you will never use in real life!
Answer:
(b² + 1) (b - 1)
Step-by-step explanation:
= b³ - b² + b - 1
= b² (b - 1) + 1(b - 1)
= (b² + 1) (b - 1)
3 consecutive odd integers....x, x + 2, and x + 4
x + x + 4 = 3(x + 2) - 131
2x + 4 = 3x + 6 - 131
2x + 4 = 3x - 125
2x - 3x = - 125 - 4
-x = - 129
x = 129
x + 2 = 129 + 2 = 131
x + 4 = 129 + 4 = 133
so ur 3 odd numbers are : 129,131, and 133 <==
Answer:
Step-by-step explanation:
Sample space is 36C4
Now, we want to know all of the combinations that have 1 digit in it.
So, we can have one here:
1XXX
X1XX
XX1X
XXX1
But we have 10 different digits to choose from. So, we need to introduce the combination term, nCr, where n is a list of all digits and r is how many we want.
Since we only want one, we will need 10C1 for the number of digits. But we need to choose three lowercases, so it becomes 10C1 × 26C3
Since it's a probability question, we need to divide that by our sample space, 36C4, and our percentage becomes 44%
