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Ugo [173]
3 years ago
10

An onsite oil change service charges a flat rate of $40.00 per service call and an additional $2.25 per mile fee for travel outs

ide a certain radius. Josh budgets $200 per year for oil changes on his vehicle. He lives 7 miles outside the radius. What is the greatest number of oil changes (c) that he can schedule and keep on budget for the year?
Mathematics
2 answers:
OLEGan [10]3 years ago
8 0

Answer:

c = 3 oil changes

Step-by-step explanation:

The fixed rate for oil change is $ 40

The surplus rate for miles outside the radius is $ 2.25

Josh lives 7 miles of the radius

Therefore an equation for c: The largest number of oil changes that can be scheduled and maintained within the budget for the year is:

\\40c + 2.25 * 7c = 200\\c (40 + 2.25 * 7) = 200\\c =\frac{200}{40 + 2.25 * 7}\\c = 3,578\\c = 3 oil changes

Therefore, with the budget set Josh can make a maximum of 3 oil changes per year

jeyben [28]3 years ago
3 0

Answer:

The answer is 3

Step-by-step explanation

mileage fee for each oil change: 7(2.25) = $15.75

service call + mileage fee = total for each oil change

$40 + $15.75 = $55.75

c = number of oil changes

55.75c = total amount for all oil changes

55.75c ≤ 200

c ≤ 3.59

Therefore, the greatest number of oil changes that Josh can schedule without exceeding his budget is 3.

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Answer:

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3 years ago
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Murrr4er [49]

Answer:

a) For this case we can use the definition of weighted average given by:

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And if we replace the values given we have:

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Step-by-step explanation:

Assuming the following question: "One sample has a mean of M=8 and a second sample has a mean of M=16 . The two samples are combined into a single set of scores.

a) What is the mean for the combined set if both of the original samples have n=4 scores "

For this case we can use the definition of weighted average given by:

M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}

And if we replace the values given we have:

M = \frac{8*4 + 16*4}{4+4}= 12

b) what is the mean for the combined set if the first sample has n=3 and the second sample has n=5

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M = \frac{8*3 + 16*5}{3+5}= 13

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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-----------------------------------------------------------

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Step-by-step explanation:

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