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Ugo [173]
3 years ago
10

An onsite oil change service charges a flat rate of $40.00 per service call and an additional $2.25 per mile fee for travel outs

ide a certain radius. Josh budgets $200 per year for oil changes on his vehicle. He lives 7 miles outside the radius. What is the greatest number of oil changes (c) that he can schedule and keep on budget for the year?
Mathematics
2 answers:
OLEGan [10]3 years ago
8 0

Answer:

c = 3 oil changes

Step-by-step explanation:

The fixed rate for oil change is $ 40

The surplus rate for miles outside the radius is $ 2.25

Josh lives 7 miles of the radius

Therefore an equation for c: The largest number of oil changes that can be scheduled and maintained within the budget for the year is:

\\40c + 2.25 * 7c = 200\\c (40 + 2.25 * 7) = 200\\c =\frac{200}{40 + 2.25 * 7}\\c = 3,578\\c = 3 oil changes

Therefore, with the budget set Josh can make a maximum of 3 oil changes per year

jeyben [28]3 years ago
3 0

Answer:

The answer is 3

Step-by-step explanation

mileage fee for each oil change: 7(2.25) = $15.75

service call + mileage fee = total for each oil change

$40 + $15.75 = $55.75

c = number of oil changes

55.75c = total amount for all oil changes

55.75c ≤ 200

c ≤ 3.59

Therefore, the greatest number of oil changes that Josh can schedule without exceeding his budget is 3.

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jolli1 [7]
Answer: a = 40, b = 50, c = 115

Solution:
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5 0
2 years ago
The probability of rain on the last day of July is 95 % . If the probability remains constant for the first seven days of August
8090 [49]

The probability that it rains at most 2 days is 0.00005995233 and the variance is 0.516

<h3>The probability that it rains at most 2 days</h3>

The given parameters are:

  • Number of days, n = 7
  • Probability that it rains, p = 95%
  • Number of days it rains, x = 2 (at most)

The probability that it rains at most 2 days is represented as:

P(x ≤ 2) = P(0) + P(1) + P(2)

Each probability is calculated as:

P(x) = ^nC_x * p^x * (1 - p)^{n - x}

So, we have:

P(0) = ^7C_0 * (92\%)^0 * (1 - 92\%)^{7 - 0} = 0.00000002097

P(1) = ^7C_1 * (92\%)^1 * (1 - 92\%)^{7 - 1} = 0.00000168821

P(2) = ^7C_2 * (92\%)^2 * (1 - 92\%)^{7 - 2} = 0.00005824315

So, we have:

P(x ≤ 2) =0.00000002097 + 0.00000168821 + 0.00005824315

P(x ≤ 2) = 0.00005995233

Hence, the probability that it rains at most 2 days is 0.00005995233

<h3>The mean</h3>

This is calculated as:

Mean = np

So, we have:

Mean = 7 * 92%

Evaluate

Mean = 6.44

Hence, the mean is 6.44

<h3>The standard deviation</h3>

This is calculated as:

σ = √np(1 - p)

So, we have:

σ = √7 * 92%(1 - 92%)

Evaluate

σ = 0.718

Hence, the standard deviation is 0.718

<h3>The variance</h3>

We have:

σ = 0.718

Square both sides

σ² = 0.718²

Evaluate

σ² = 0.516

This represents the variance

Hence, the variance is 0.516

Read more about normal distribution at:

brainly.com/question/4079902

#SPJ1

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Answer:

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3 years ago
Makayla borrows $15200. Some is from her friend at 5% annual interest, 2 times as much as that from her bank at 8% , and the rem
GalinKa [24]

Answer:

Amount borrowed from friend = 4000

From Bank = 8000

From insurance = 3200

Step-by-step explanation:

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Amount borrowed = $15200

Let amount borrowed from friend = x

x at 5% = 0.05x

From Bank = 2x at 8% = 0.08*2x = 0.16x

From insurance = 15200 - (x + 2x) at 4%

From insurance = 15200 - 3x at 4% ; (15200 - 3x)* 0.04 = 608 - 0.12x

Interest paid in first year = $968

Simple interest = principal * rate * time

968 =

968 = (0.05x + 0.16x + 608 - 0.12x)

968 - 608 = 0.05x + 0.16x - 0.12x

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x = 360 / 0.09

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Amount borrowed from friend = 4000

From Bank = 2x = 4000 * 2 = 8000

From insurance = 15200 - (4000 + 8000) = 3200

4 0
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