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Romashka [77]
3 years ago
10

Write a real world problem that can be solved by the equation y+8=20

Mathematics
2 answers:
DochEvi [55]3 years ago
6 0
Phil started with 20 cookies and now there are 8 how many cookies did phil eat?
20-8=12 so phil ate 12 out of 20 cookies
Oduvanchick [21]3 years ago
6 0
<span>Cary and Mary have 15 cupcakes.Mary has 9 cupcakes.How many cupcakes does Cary have?
y+9=15

Subtract 9 from both sides.

y = 6

Cary has 6 cupcakes</span>
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Each student wrote a two-step equation. Peter wrote the equation 4x-2=10, and Andres wrote the equation 16x-8=40. The teacher lo
natima [27]
Both variables (x) are 3.

4×3=12
12-2=10

16×3=48
48-8=40

3 fits the variable of the missing number.
8 0
3 years ago
Multiply two and four-fifths negative five and two-thirds
Cerrena [4.2K]
The answer is -25/3.



If you need it simplified let me know.
4 0
3 years ago
Please answer this fast in two minutes
Musya8 [376]

Answer:

65 degrees.

Step-by-step explanation:

If LN and OQ are parallel, and QPM is 115, then LMK is also 115. LMP is the supplement, so it would be 65

Hope this helps!

6 0
3 years ago
Read 2 more answers
Nikki has $1100 and spends $35 per week. Mich has $520 and saves $55 per week. In about how many weeks, will Nikki and Micah hav
Rashid [163]

Answer:

6 weeks

Step-by-step explanation:

Given that :

Nikki :

Initial amount = $1100 ;

Amount spent per week = $35

Mich:

Initial amount = $520

Amount saved per week = $55

Number of weeks they'll both have the same amount :

Let number of weeks = w

For Nikki who is spending :

1100 - 35w - - - (1)

For Mich who is saving :

520 + 55w - - - (2)

Equate (1) and (2)

1100 - 35w = 520 + 55w

1100 - 520 = 55w + 35w

580 = 90w

w = 580 / 90

w = 6.444

About 6 weeks

5 0
3 years ago
Find sin (A-B) if sin A = 4/5 with A between 90 and 180 and if cos B = 3/5 with B between 0 and 90
quester [9]

Answer:

sin(A-B) = 24/25

Step-by-step explanation:

The trig identity for the differnce of angles tells you ...

sin(A -B) = sin(A)cos(B) -sin(B)cos(A)

We are given that sin(A) = 4/5 in quadrant II, so cos(A) = -√(1-(4/5)^2) = -3/5.

And we are given that cos(B) = 3/5 in quadrant I, so sin(B) = 4/5.

Then ...

sin(A-B) = (4/5)(3/5) -(4/5)(-3/5) = 12/25 + 12/25 = 24/25

The desired sine is 24/25.

3 0
3 years ago
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