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Romashka [77]
3 years ago
10

Write a real world problem that can be solved by the equation y+8=20

Mathematics
2 answers:
DochEvi [55]3 years ago
6 0
Phil started with 20 cookies and now there are 8 how many cookies did phil eat?
20-8=12 so phil ate 12 out of 20 cookies
Oduvanchick [21]3 years ago
6 0
<span>Cary and Mary have 15 cupcakes.Mary has 9 cupcakes.How many cupcakes does Cary have?
y+9=15

Subtract 9 from both sides.

y = 6

Cary has 6 cupcakes</span>
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Factor 8c + 10c?.<br> ✅p
Rashid [163]

Answer: 18 c

Step-by-step explanation: since they have the same variables you can easily just add them together

7 0
4 years ago
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What is the equation of the function that is graphed as line a?
valentinak56 [21]
F(x)=-1x-1

1)  Pick 2 points on the line (i chose (-4,3) and (3,-4)
2) Find slope of the line using the 2 points. (work below)
3) Find y-intercept, which is the point where y-axis and the line cross (y-intercept is -1).
4) Place both slope and y-intercept into slope-intercept form, y=mx+b (m=slope and b=y-intercept.)
5) Change y to f(x) (meaning function of x).

Work:
3-(-4)/-4-3=3+4/-4-3=7/-7=-1

y-intercept equals -1 also.

y=mx+b
y=-1x+(-1)
y=-1x-1
f(x)=-1x-1<---Answer

6 0
4 years ago
5 questions plz answer all of them if you do you will get points, thanks, Brainliest answer,
babunello [35]
1. 1/6

2. 1/8

3. 80%

4. 1/5

5. 2/8 or 25%
5 0
3 years ago
The figure shows the dimensions of a backyard
Ulleksa [173]
Answer:

570yd^2

step by step:

Split the backyard into 2 different rectangles and add the areas together. I did 8x30 and 15x22.
8 0
3 years ago
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In the game of blackjack played with one​ deck, a player is initially dealt 2 different cards from the 52 different cards in the
Volgvan

Answer:

P =4.83\%

Step-by-step explanation:

First we calculate the number of possible ways to select 2 cards an ace and a card of 10 points.

There are 4 ace in the deck

There are 16 cards of 10 points in the deck

To make this calculation we use the formula of combinations

nCr=\frac{n!}{r!(n-r)!}

Where n is the total number of letters and r are chosen from them

The number of ways to choose 1 As is:

4C1 = 4

The number of ways to choose a 10-point letter is:

16C1 = 16

Therefore, the number of ways to choose an Ace and a 10-point card is:

4C1 * 16C1 = 4 * 16 = 64

Now the number of ways to choose any 2 cards from a deck of 52 cards is:

52C2 =\frac{52!}{2!(52-2)!}

52C2 = 1326

Therefore, the probability of obtaining an "blackjack" is:

P = \frac{4C1 * 16C1}{52C2}

P = \frac{64}{1326}

P = \frac{32}{663}

P =0.0483

P =4.83\%

4 0
3 years ago
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