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Nezavi [6.7K]
3 years ago
13

Which three-dimensional figure is formed by the rotation given?

Mathematics
2 answers:
marysya [2.9K]3 years ago
5 0
A line being rotated in such a way I would think would be A
valkas [14]3 years ago
5 0

Answer:

A.

Step-by-step explanation:

It would give the bowl on the left.. That is option A.

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The average weight of David, Esther, and Henry is 42.6 kg. Esther is twice as heavy as Henry. David is 5.2 kilograms lighter tha
kari74 [83]

Answer:

  53.2 kg

Step-by-step explanation:

Let E represent Esther's weight. Then Henry's weight is E/2, and David's weight is E-5.2. Their average weight is ...

  ((E-5.2) + E + (E/2))/3 = 42.6

  2.5E -5.2 = 127.8 . . . . . . . . . . multiply by 3, simplify

  2.5E = 133 . . . . . . . . . . . . . . . . add 5.2

  E = 133/2.5 = 53.2 . . . . kg

Esther's weight is 53.2 kg.

7 0
3 years ago
Find the explicit formula for the general nth term of the arithmetic sequence described below. Simplify the formula and reduce a
NemiM [27]

Answer:

an = 4/3n - 13/3.

Step-by-step explanation:

The first term is a1,

a24 = a1 + 23d

83/3 = a1 + 4/3* 23

a1 =    83/3 - 92/3

a1 = -9/3 = -3.

So the nth term an =  -3 + 4/3(n - 1)

an = -3 + 4/3 n - 4/3

an = 4/3n - 13/3

6 0
3 years ago
Help I need an answer ASAP will give brainliest
MrMuchimi
The answer is a=6, b=4, and 0=3 you can always try to find the answer in google though

Hope that helped
6 0
2 years ago
How do I do lesson 12 grade 6 problem set
myrzilka [38]
Umm.. I have to see the problems, we might not have the same textbooks so
8 0
2 years ago
Read 2 more answers
Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ
In-s [12.5K]
PART A

The equation of the parabola in vertex form is given by the formula,

y - k = a {(x - h)}^{2}

where

(h,k)=(1,-2)

is the vertex of the parabola.

We substitute these values to obtain,


y  + 2 = a {(x - 1)}^{2}

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.


6  + 2 = a {(3 - 1)}^{2}


8= a {(2)}^{2}


8=4a


a = 2
Hence the equation of the parabola in vertex form is


y  + 2 = 2 {(x - 1)}^{2}


PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

y  + 2 = 2{(x - 1)}^{2}

This implies that

y + 2 = 2(x - 1)(x - 1)


We expand to obtain,


y + 2 = 2( {x}^{2}  - 2x + 1)


This will give us,


y + 2 = 2 {x}^{2}  - 4x + 2


y =  {x}^{2}  - 4x

This equation is now in the form,

y = a {x}^{2}  + bx + c
where

a=1,b=-4,c=0

This is the standard form
7 0
3 years ago
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