Question

Solve quadratic formulax^2-4x+3=0

Answer 1

The general formula for a equation of the form:

$ax^2+bx+c=0$

is:

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

In this case we notice that a=1, b=-4 and c=3. Plugging this values in the general formula we get:

$\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(1)(3)}}{2(1)} \\ =\frac{4\pm\sqrt[]{16-12}}{2} \\ =\frac{4\pm\sqrt[]{4}}{2} \\ =\frac{4\pm2}{2} \end{gathered}$

then:

$x_1=\frac{4+2}{2}=\frac{6}{2}=3$

and

$x_2=\frac{4-2}{2}=\frac{2}{2}=1$

Therefore, x=3 or x=1.