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VladimirAG [237]
1 year ago
13

Solve quadratic formulax^2-4x+3=0

Mathematics
1 answer:
bekas [8.4K]1 year ago
8 0

The general formula for a equation of the form:

ax^2+bx+c=0

is:

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

In this case we notice that a=1, b=-4 and c=3. Plugging this values in the general formula we get:

\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(1)(3)}}{2(1)} \\ =\frac{4\pm\sqrt[]{16-12}}{2} \\ =\frac{4\pm\sqrt[]{4}}{2} \\ =\frac{4\pm2}{2} \end{gathered}

then:

x_1=\frac{4+2}{2}=\frac{6}{2}=3

and

x_2=\frac{4-2}{2}=\frac{2}{2}=1

Therefore, x=3 or x=1.

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