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Aliun [14]
4 years ago
8

Y/5 + 1 divided by y^2/25-1=

Mathematics
2 answers:
Alex73 [517]4 years ago
8 0

Answer:

5/y-5

Step-by-step explanation:

y/5+1/y^2/25-1=1/y/5-1

Inessa [10]4 years ago
7 0

<u>Answer:</u>

The value of \frac{\left(\frac{y}{5}\right)+1}{\left(\frac{y^{2}}{25}\right)-1}=\frac{5}{y-5}

<u>Solution:</u>

As given, \frac{\left(\frac{y}{5}\right)+1}{\left(\frac{y^{2}}{25}\right)-1}

\frac{\left(\frac{y}{5}\right)+1}{\left(\frac{y}{5}\right)^{2}-1^{2}}

\frac{\frac{y}{5}+1}{\left(\frac{y}{5}+1\right) \times\left(\frac{y}{5}-1\right)}

as we know \left(a^{2}-b^{2}\right)=(a+b)\times(a-b)

This can be written as,

\Rightarrow \frac{\frac{y}{5}+1}{\frac{y}{5}+1} \times \frac{1}{\frac{y}{5}-1}

Because \Rightarrow \frac{\frac{y}{5}+1}{\frac{y}{5}+1}=1

\Rightarrow 1 \times \frac{1}{\frac{y}{5}-1} = \frac{5}{y-5}

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