Answer:
a) 3x⁴-4x³-8x²-35x-10
Step-by-step explanation:
3x2(x²-3x-1)+5x(x²-3x-1)+10(x²-3x-1)
3x⁴-9x³-3x²+5x³-15x²-5x+10x²-30x-10
3x⁴-9x³+5x³-3x²-15x²+10x²-5x-30x-10
3x⁴-4x³-8x²-35x-10
<span>going downstream -
t = 14/(2 + v)
going upstream -
t = 7/(2 - v)
14/(2 + v) = 7/(2 - v)
(2 + v)/2 = 2 - v
v = 2/3km/h</span><span>
</span>
Answer:
Height of flagpole before it fell = 5.15 m
Step-by-step explanation:
Given:
Height of remain pole (p) = 1.7 m
Distance from base (b) = 3 m
Find:
Height of flagpole before it fell
Computation:
Using Pythagorean theorem
H = √ p² + b
Length of broken part = √ 1.7² + 3²
Length of broken part = √ 2.89 + 9
Length of broken part = √ 11.89
Length of broken part = 3.45 (Approx)
Height of flagpole before it fell = Length of broken part + Height of remain pole
Height of flagpole before it fell = 3.45 + 1.7
Height of flagpole before it fell = 5.15 m
In 1 ounce, there is approximately 28.34 grams.
I'm not sure if this is the easiest way of doing this, but it surely work.
Let the base of the triangle be AB, and let CH be the height. Just for reference, we have
Moreover, let CH=y and BC=z
Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system
If we solve the first two equations for y squared, we have
And we can deduce
So that the third equation becomes
(we can't accept the negative root because negative lengths make no sense)
