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vampirchik [111]

2 years ago

12

Adam plans to choose a video game from a section of the store where everything is

1 answer:

alexira [117]2 years ago

4 0

Original price of video game minus the sale price (-.75d) = the percent of original price Adam will pay (.25d)

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514 divided by 28 equals?

Ulleksa [173]

514 divided by 28 equals 18.3571429

5 0

3 years ago

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At a local fitness center, members pay a $10 membership fee and $5 for each aerobics class. Nonmembers pay $6 for each aerob

sveta [45]

One way to solve it is writing two equations based on the info so

y = 5x + 10 for members
y = 6x for nonmembers

(the + 10 isn't included in the second equation because nonmembers won't pay a membership fee)

and to find their intersection point (where the values will be the same), you just set them equal to each other:

5x + 10 = 6x

subtract 5x

x = 10 classes

7 0

3 years ago

The signs of the product of 263 and 0 is

Mashcka [7]

The answer to the question is 0

6 0

3 years ago

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Cheryl wants to have $2300 in spending money to take on a trip to Disney World in three years. How much must she deposit now in

Savatey [412]

Use the compound amount formula:

$2,300 = P(1+0.02)^3. Solve this for P:

P = $2,300 / (1.02)^3 = $2167.34.

By depositing $2,167.34 now, Cheryl would have $$2300 after three years.

4 0

3 years ago

Find the equation of a line that passes through (-5,4) and us parallel to y=-6/7x+3

irina [24]

Given:

The given equation of line is

$y=-\dfrac{6}{7}x+3$

To find:

The equation of line that passes through (-5,4) and is parallel to the given line.

Solution:

Slope intercept form of a line is

$y=mx+b$ ...(i)

where, m is slope and b is y-intercept.

We have,

$y=-\dfrac{6}{7}x+3$ ...(ii)

On comparing (i) and (ii), we get

$m=-\dfrac{6}{7}$

Slope of given line is $m=-\dfrac{6}{7}$ .

Slope of parallel lines are same. So, slope of parallel line is $m=-\dfrac{6}{7}$ .

The required line passes through (-5,4) with slope $m=-\dfrac{6}{7}$ . So, the equation of line is

$y-y_1=m(x-x_1)$

$y-4=-\dfrac{6}{7}(x-(-5))$

$y-4=-\dfrac{6}{7}(x+5)$

$y-4=-\dfrac{6}{7}x-\dfrac{30}{7}$

Adding 4 on both sides, we get

$y=-\dfrac{6}{7}x-\dfrac{30}{7}+4$

$y=-\dfrac{6}{7}x+\dfrac{-30+28}{7}$

$y=-\dfrac{6}{7}x-\dfrac{2}{7}$

Therefore, the correct option is a.

8 0

3 years ago