Until 2015, each new Roblox user automatically had one friend and the friend was called Builderman
Builderman is the friend that is provided automatically for all users until 2015
<h2>Further Explanation</h2>
The builderman welcomes each new Roblox user, send a message to them and automatically follows every user until when it was discontinued in 2014. The role of the Builderman was to introduce the game experience to each new Roblox user.
Roblox is an online game and serves as a platform where users can also create their own games. Roblox gives its users the platform to design their own games and allow its user to different kinds of games that are created by other users on the platform
Roblox hosts numerous games designed by its users and virtual worlds which covers different genres, such as traditional racing, obstacle courses and many more.
Roblox has millions of users worldwide, its monthly active users are over 100million. Roblox also allows its users to create virtual items for sale. This also implies, its users can create virtual items and sell them for other users
Roblox was founded by David Baszucki and Erik Cassel; it was released on September 1, 2006. It is a platform that allows single-player and multiplayer.
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KEYWORDS:
- roblox
- builderman
- friend
- message
- automatically
- david baszucki
- erik cassel
Answer:
double x = 2.5;
double y = -1.5;
int m = 18;
int n = 4;
string s = "Storm";
string t = "Watch";
The output of the expression "x + n*y - (x+n)*y" is "6.25".
and the output of expression "m/n + m%n" is "6".
Explanation:
for the first expression,
x + n*y - (x+n)*y ,put value of every variables in it.
=2.5+4*(-1.5)-(2.5+4)*(-1.5)
=2.5-6.0-(6.5*(-1.5)
=-3.5+9.75
=6.25
for the second expression,
m/n + m%n, put value of every variables in it.
=18/4 +18%4
=4+2 ("/ will give quotient and % will give remainder")
=6
Answer:
False
Explanation:
No app icon on app's action bar will move the device to its home screen.It is not a valid statement.
Answer:
from collections import Counter
def anagram(dictionary, query):
newList =[]
for element in dictionary:
for item in query:
word = 0
count = 0
for i in [x for x in item]:
if i in element:
count += 1
if count == len(item):
newList.append(item)
ans = list()
for point in Counter(newList).items():
ans.append(point)
print(ans)
mylist = ['jack', 'run', 'contain', 'reserve','hack','mack', 'cantoneese', 'nurse']
setter = ['ack', 'nur', 'can', 'con', 'reeve', 'serve']
anagram(mylist, setter)
Explanation:
The Counter class is used to create a dictionary that counts the number of anagrams in the created list 'newList' and then the counter is looped through to append the items (tuple of key and value pairs) to the 'ans' list which is printed as output.
