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dsp73
3 years ago
11

Which of the following is a list of input devices?

Computers and Technology
1 answer:
charle [14.2K]3 years ago
7 0
The Correct answer would be C. <span>microphone,mouse,scanner

microphone you talk into to give info (data)

a mouse you use to click on objects  to give input 

a scanner you input a paper/object 

hope this helps!! :)


</span>
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Define reverse engineering in hacker context
bogdanovich [222]
Taking the product and taking it apart to insert a malicious process into it, then implement it into the world.

Hope this helps.
3 0
3 years ago
What shooting position is commonly used when hunting with a shotgun?
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Standing well for me I never miss a shot in that position

6 0
4 years ago
Read 2 more answers
Lab Assignment 7A For the lab this week, you will sort an array - using any of the sort methods discussed in Chapter 23 or the S
zhuklara [117]

Answer:

See explaination

Explanation:

import java.util.Scanner;

public class sort {

static void lowestToHighest(float arr[][])

{

float temp;

for(int i=0;i<11;i++)

for(int j=0;j<12-i-1;j++) //Using bubble sort to sort

{

if(arr[j][0]>arr[j+1][0])

{

temp = arr[j][0];

arr[j][0] = arr[j+1][0];

arr[j+1][0] = temp;

}

}

for(int i=0;i<11;i++) //Using bubble sort to sort

{

for(int j=0;j<12-i-1;j++)

if(arr[j][1]>arr[j+1][1])

{

temp = arr[j][1];

arr[j][1] = arr[j+1][1];

arr[j+1][1] = temp;

}

}

System.out.println("Data in the array after sorting lowest to highest: ");

for(int i=0;i<12;i++)

System.out.printf(arr[i][0]+" "+arr[i][1]+"\n");

}

static void highestToLowest(float arr[][])

{

float temp;

for(int i=0;i<11;i++)

for(int j=0;j<12-i-1;j++) //Using bubble sort to sort

{

if(arr[j][0]<arr[j+1][0])

{

temp = arr[j][0];

arr[j][0] = arr[j+1][0];

arr[j+1][0] = temp;

}

}

for(int i=0;i<11;i++) //Using bubble sort to sort

{

for(int j=0;j<12-i-1;j++)

if(arr[j][1]<arr[j+1][1])

{

temp = arr[j][1];

arr[j][1] = arr[j+1][1];

arr[j+1][1] = temp;

}

}

System.out.println("Data in the array after sorting highest to lowest: ");

for(int i=0;i<12;i++)

System.out.printf(arr[i][0]+" "+arr[i][1]+"\n");

}

public static void main(String[] args){

float temperature[][]=new float[12][2];

Scanner input = new Scanner(System.in);

System.out.println("Enter 12 months of highest and lowest temperatures for each month of the year: ");

for(int i=0;i<12;i++)

for(int j=0;j<2;j++)

temperature[i][j]=input.nextFloat();

System.out.println("Data in the array: ");

for(int i=0;i<12;i++)

System.out.printf(temperature[i][0]+" "+temperature[i][1]+"\n");

lowestToHighest(temperature);

highestToLowest(temperature);

}

}

8 0
4 years ago
Pseudocode of creating a program to convert to IEEE 754 to a real number
Eduardwww [97]

Answer:

  • Step1: Check If the number is Positive or Negative.  
  • Step2: If it is positive then save the sign of it as 0.  
  • Step3: If it is negative then save the sign of it as 1.
  • Step4: Covert the negative number to Positive.
  • Step5: Convert the IEEE 754 to Binary.
  • Step6: convert the integer part into binary form  
  • Step7: Convert fractional part into binary form
  • Step8: To convert Integer part, Devide the number by 2 and note down the reminder and Keep deviding unless dividend is less than 2
  • Step9: copy all the reminders together
  • Step10: Multiply decimal part by 2 unless fractional part is 0.
  • Step11: By noting down integral part, keep multiplying decimal part by new value of 2 untill perfect number is reached.
  • Step6: Find the Mantissa.
  • Step7: Concatinate the Sign, exponent and the mantissa.

Explanation:

For Example : 20.75

First step (converting 50 (in base 10) to binary):

  • No is Positive
  • By dividing 20 by 2, which gives 10 with no remainder 0.
  • Now Devide 10 by 2, which gives 5 with a remainder of 0.
  • Now Devide 5 by 2, which gives 2 the reminder as 1
  • Now Devide 2 by 2, which gives 1 with reminder as 0
  • Now devide 1 by 2, which gives 0 with reminder as 1
  • We read the result from bottom to top  which is 10100

Second part is to convert 0.75 to binary:

  • We have to multiply 0.75 by 2, which gives 1.5. We keep only the integer part, which is 1.  
  • Now, we do 1.5 - 1, which gives 0.5. Now, We multiply 0.5 by 2, which gives 1.  
  • Now we do 1 - 1, which gives 0.
  • Reading from Top to bottom will give 110

Final Answer is : 10100.110

8 0
3 years ago
File " ", line 1
lilavasa [31]

Answer:

i = 1

while i < 11:

 print("The Indian High School")

 i += 1

3 0
3 years ago
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