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2 years ago

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Besides replicating DNA, what is another function of DNA polymerase?

2 answers:

saul85 [17]2 years ago

7 0

<span>Besides replicating DNA,another function of DNA polymerase is "Protein Synthesis"

In short, Your Answer would be Option A

Hope this helps!</span>

Genrish500 [490]2 years ago

6 0

The correct answer is correcting errors.

The prime activity of DNA polymerase is to synthesize DNA from nucleotides, that is, the building blocks of DNA. There are many kinds of DNA polymerase, which does an essential role in the replication of DNA and they generally function in pairs to duplicate one molecule of double-stranded DNA into two novel double-stranded molecules of DNA.

Apart from developing new copies of DNA, the DNA polymerase is accountable for proofreading the strand so that the misplaced or the wrong base pairs can be corrected. This maintains the veracity of the original strand of DNA, which is passed onto the daughter cells.

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Aqueous hydrobromic acid will react with solid sodium hydroxide to produce aqueous sodium bromide and liquid water . Suppose 17.

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<u>Answer:</u> The mass of NaBr that can be produced is 6.3 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

<u>For HBr:</u>

Given mass of HBr = 17 g

Molar mass of HBr = 81 g/mol

Putting values in equation 1, we get:

$\text{Moles of HBr}=\frac{17g}{81g/mol}=0.210mol$

<u>For NaOH:</u>

Given mass of NaOH = 2.44 g

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

$\text{Moles of NaOH}=\frac{2.44g}{40g/mol}=0.061mol$

The chemical equation for the reaction of HBr and NaOH follows:

$HBr+NaOH\rightarrow NaBr+H_2O$

By Stoichiometry of the reaction:

1 mole of NaOH reacts with 1 mole of HBr

So, 0.061 moles of NaOH will react with = $\frac{1}{1}\times 0.061=0.061mol$ of HBr

As, given amount of HBr is more than the required amount. So, it is considered as an excess reagent.

Thus, NaOH is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of NaOH produces 1 mole of NaBr

So, 0.061 moles of NaOH will produce = $\frac{1}{1}\times 0.061=0.061moles$ of carbon dioxide

Now, calculating the mass of NaBr from equation 1, we get:

Molar mass of NaBr = 103 g/mol

Moles of NaBr = 0.061 moles

Putting values in equation 1, we get:

$0.061mol=\frac{\text{Mass of NaBr}}{103g/mol}\\\\\text{Mass of NaBr}=(0.061mol\times 103g/mol)=6.28g$

Hence, the mass of NaBr that can be produced is 6.3 grams

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