I would start by converting g/mL to g/L
75.00g/1000.0mL = 75.00g/L
Stoichiometrically, flip 75 onto the bottom so that grams cancel out and we are left with the number of L required.
(L/75.00g)(15g) -> this is essentially dividing 15g by 75g, which cancels the unit g, leaving us with 0.2L. If the question requires an answer in mL, just multiple the number of L by 1000.
The patient requires 200mL of glucose solution to receive his 15g of glucose.
Answer: 1-82 2-7.4 3-355 4-.93
Explanation:
answers on edg
Answer:
Explanation:
<em>First calculate how many moles of O2 you have. O is 16g/mole, so O2 is 32g/mole. 50/32 = 1.5625 moles. 1 mole of any gas at stp is 22.4 liters.</em>
<em>1.5625 × 22.4 = 35 liters.</em>
<em>Its been 15 years since I graduated HS, and I still remember how to do this. Do your own homework next time and in 15 years you may be able to do the same.</em>
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B. A los to cover a coffee mug
I think it would be 2,510 kJ, or 2,510,000 J.
