frogs,toads,snakes,lizards
Answer:
Explanation:
Using the Mendelian approach to solve this question, we will understand that the mendelian approach has a pattern for inherited traits.
From the data set given, the total number of the population is:
43+9+32+110 = 194
However, their ratio are being calculated as follows:
43/194 = 0.22
9/194 = 0.05
32/194 = 0.16
110/194 = 0.57
After comparison with the Mendelian's approach, we realize that these results seem to be similar to the 9:3:3:1 ratio.
i.e.
3/16 = 0.18
1/16 = 0.06
3/16 = 0.18
9/16 = 0.56
The inheritance pattern obviously dictates that the flax experiment proceeds in the pattern found in the Mendelian's Approach and the resistance of the two different strains were arbitrated by two traits.
Answer:
<em>The correct option is A. Nucleotide sequence, human, hemoglobin</em>
Explanation:
If the segment of the DNA for the human gene is known then it will be very easy to find the gene on a database. The tags which should be used will be the nucleotide sequence, where the known sequence shall be mentioned.
Then we will choose the tag for the organism which is humans in this case. Then we will select the tag for the protein which is made by the nucleotide sequence, which is protein in this case. Hence, option A is the correct answer.
0.1 M solution of a disaccharide solution will contain 2000 monosaccharide molecules.
<h3>What are monosaccharides?</h3>
Monosaccharides, also known as simple sugars are the simplest monomers of carbohydrates which may either be 3 carbon, 4 carbon, 5 carbon, 6 carbon or 7 carbo compounds.
There are two types of monosaccharides;
- aldoses sugars, e.g. glucose, and
- ketose sugars e.g. fructose.
When two monosaccharides are linked together by glycosidic bonds to form a single compound, the compound formed is called a disaccharide.
Considering the give question:
Suppose a 0.1M solution of a monosaccharide contains 1000 monosaccharide molecules. How many monosaccharide molecules would be in a 0.1 M solution of a disaccharide.
The number of monosaccharides molecules present in the 0.1 M solution of a disaccharide is determined as follows:
1 disaccharide molecule contains 2 monosaccharide molecules
0.1M solution of a monosaccharide contains 1000 monosaccharide molecules.
0.1 M solution of a disaccharide will contain 2 * 1000 monosaccharide molecules
0.1 M solution of a disaccharide will contain = 2000 monosaccharide molecules.
Learn more about monosaccharides and disaccharides at: brainly.com/question/731310
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