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3 years ago

13

Each of the p children at a park receive 3 balloons. If the children receive at least 150 balloons in all, find the minimum numb

er of children at the park.

1 answer:

kramer3 years ago

4 0

The answer is 50. you would divide 150 by 3.

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Help me out plz bcbxbxbxhx

Ludmilka [50]

Multiply by 5 is correct

5 0

2 years ago

Read 2 more answers

Round to the nearest thousand and then add the rounded numbers. <br><br> 8794<br> +312

lyudmila [28]

Answer:

4.0148 rounded to the nearest thousand is 0, but if you meant rounded to the nearest thousandth, it would be 4.015 because the 8 in the ten thousandth column would cause the 4 in the thousandth column to round up to 5.

Step-by-step explanation:

7 0

3 years ago

Karina uses the system of equations below to compare the monthly utility costs in July and December for electricity, x, and natu

fiasKO [112]

Answer:

d. The cost of natural gas (y) = $0.83 per unit

Step-by-step explanation:

The explanation is shown below:-

the equation of system is:

750x + 17y = 141.61 (i)

300x + 30y =75.90 (ii)

as x indicates the cost of electricity and y indicates the costs of natural gas.

we will solve the both equation with the help of multiplication for (i) by 30 and for (ii) 75

$30\times (750x + 17y) 30\times 141.61\\\\$

after solve the above equation we will get

22,500x + 510y = 4248.3 (iii)

$75\times (330x + 30y) = 75\times 75.90$

after solve the above equation we will get

22500x + 2250y = 5692.5 (iv)

After deducting the equation (iii) and (iv) we will get

1740 y = 1444.2

After Dividing by 15 both sides,

116y = 96.28

So, Katrina simplify the above system using linear equation and reach at the equation that is

116 y = 96.28

By Division property of equality defines that divide the equal no. of both sides of an equation:

by Division of 116 to both sides of an equation, to get y:

$\frac{116y}{116} = \frac{96.28}{116}$

y = 0.83

So, the natural gas is $0.83 per unit

7 0

3 years ago

A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe

Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

$Volume=\frac{1}{2} (b_{1}+4+2x)h X H$

$Volume=\frac{1}{2} (4+4+2x)h X 16$

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

$V=64h+16h(\frac{h}{4})$

$V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}$

h=3m,

dV/dt=25cm/min=0.25 m/min

$0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}$

=0.002841m/min =0.28cm/min

The rate is the water being drawn from the trough is 0.28cm/min.

3 0

3 years ago

plllllllllllllllllllllllllllllllllllllllllllllllllzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

evablogger [386]

the answer is D

reason: ration of freshmen to sophmores is 17 to 19, for other way around, flip the num ber

7 0

2 years ago