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Triss [41]
3 years ago
15

What sine function represents an amplitude of 4, a period of pi over 2, no horizontal shift, and a vertical shift of −3?

Mathematics
1 answer:
mixer [17]3 years ago
4 0

Answer:

f(x) = 4sin(\frac{\pi}{2}x) - 3, the third one

Step-by-step explanation:

Explaining the sine function:

The sine function is defined by:

S = Asin(p(x - x_{0})) + V

In which A is the amplitude, p = \frac{2\pi}{N} is the period, x_{0} is the horizontal shift and V is the vertical shift.

So, in your problem:

The amplitude is 4, so A = 4.

The period is \frac{\pi}{2}, so p = \frac{\pi}{2}.

There is no horizontal shift, so x_{0} = 0.

The vertical shift is −3, so V = -3.

The sine function that represents these following conditions is

f(x) = 4sin(\frac{\pi}{2}x) - 3, the third one

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ra1l [238]

Option B: FECBAD represents the Hamilton path

Explanation:

The vertices in the given graph are A,B,C,D,E and F

We need to determine the Hamilton path of the given graph.

By definition, we know that a Hamilton path touches each and every vertex in a graph exactly once.

Hence, we need to connect the vertices in such a way that the graph touches each and every vertex exactly once.

Option A: EFADECBA

From this description, we can see that the path starts from the vertex E and connects all the vertices but some of the vertices are repeated twice.

Hence, the path EFADECBA is not a Hamilton path.

Therefore, Option A is not the correct answer.

Option B: FECBAD

From this description, we can see that the path starts from the vertex F and connects all the vertices exactly once.

Hence, the path FECBAD is the Hamilton path.

Therefore, Option B is the correct answer.

Option C: ADEFBC

From this description, we can see that the path starts from the vertex A and connects all the vertices but the path from F to B has to touch the vertex A. Thus, the vertices are repeated twice.

Hence, the path ADEFBC is not a Hamilton path.

Therefore, Option C is not the correct answer.

Option D: ADECBAFE

From this description, we can see that the path starts from the vertex A and connects all the vertices but some of the vertices are repeated twice.

Hence, the path ADECBAFE is not a Hamilton path.

Therefore, Option D is not the correct answer.

6 0
3 years ago
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Step-by-step explanation:

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valentinak56 [21]
To make calculation easier, we first multiply
1.35 × 100 = 135

then we need to find how many groups of 5 are there in 135.
to do so, we simply take 
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therefore, the answer is <u>27.</u>
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2 years ago
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Answer:

y= -2x+3

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