Answer:
See below
Step-by-step explanation:
I will assume the given denominator is 3a as there is nothing attached to the statement.
Lets first look at the domain of 2a+b. As it is a polynomial with unknowns a and b, we know it has its domain in all real numbers for both a and b as every polynomial does. For verifying it replace a and b by any real number you can think of.
Domain = a, b belonging to R
Now, if we divide 2a+b by 3a we will have:
(2a+b)/3a
As know we don not have a polynomial we cant state that the domain will still be all the real numbers for sure. We need to go further.
We have a fraction and as every fraction the denominator CAN'T be equal to 0, so 3a MUST be different to 0. This means that a MUST be different to 0. So, now our domain changes:
domain' = a, b belonging to R and a different to 0.
A 7/4 because the slope of the line is 7/4
Answer:
y = x/4 + 5
Step-by-step explanation:
Solve for y:
20 - 4 y = -x
Hint: | Isolate terms with y to the left-hand side.
Subtract 20 from both sides:
-4 y = -x - 20
Hint: | Solve for y.
Divide both sides by -4:
Answer: y = x/4 + 5
<u>Answer:</u>
x = 4 (extraneous solution)
<u>Step-by-step explanation:</u>

This solution is extraneous. Reason being that even if it can be solved algebraically, it is still not a valid solution because if we substitute back
, we will get two fractions with zero denominator which would be undefined.
Answer:

Step-by-step explanation:

hope this helps you.
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have a nice day!