Write in standard form. y=-(x-3)^2+2
1 answer:
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Answer:
B'(16,14)
Step-by-step explanation:
First find the coordinates of the vertex B. The center of the square M is the midpoint of the diagonal AC. Since A(2,7) and C(8,1), the center has coordinates
Point M is also the midpoint of the diagonal BD. Let B has coordinates (x,y), then
Hence, B(8,7).
Now, the dilation by a scale factor 2 with the center of dilation at the origin has the rule
(x,y)→(2x,2y).
Thus,
B(8,7)→B'(16,14).
Answer:
We want to graph the inequality:
3x - 2y ≤ 6
The first step is to write this as a linear equation, to do it, we can isolate y in one side of the inequality.
3x ≤ 6 + 2y
3x - 6 ≤ 2y
(3/2)x - 6/2 ≤ y
(3/2)x - 3 ≤ y
or:
y ≥ (3/2)x - 3
Because we have the symbol ≥
The points on the line are solutions, then the first part is to graph the line:
y = (3/2)*x - 3
Next, we have:
y equal to or larger than (3/2)*x - 3
Then we need to shade all the region above that line.
The graph can be seen below.
