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Zarrin [17]
3 years ago
8

If anyone could help it would be greatly appreciated

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer:

Step-by-step explanation:

area of one triangle=(1/2)×6×4=12 m²

area of four triangles=4×12=48 m²

area of square=6×6=36 m²

total area=48+36=84 m²

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The sum of x and 10 is less than -6​
goldenfox [79]
Try breaking these into sections.

Twice: 2 times

The sum of: add

A number: choose a variable, like x

---Thus "the sum of a number and 4" becomes "add x and 4" which, mathematically, is "x+4"

-----Continuing to put it all together, "Twice the sum of a number and four" becomes "2 times (x+4)" which, mathematically, is "2(x+4)"

Is: equals

-------"Twice the sum of a number and four is" becomes "2(x+4)="

23 less than: subtract 23. This one tends to trick people; "23 less than" will become "__ - 23", NOT "23 - __"

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6 0
3 years ago
Evaluate the following: 18 + 3 16 - 251 - 11
VLD [36.1K]

Answer:

18+316−251−11

=72

Step-by-step explanation:

18+316−251−11

=334−251−11

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3 0
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Danielle needs to walk 2.5 miles. If she wants to reach her destination in 30 minutes (1/2hour), how fast does she need to walk?
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Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
3 years ago
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