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SpyIntel [72]
4 years ago
9

4. Find the surface area of a triangular prism with height 30 inches, and a right triangle base with side lengths 15 inches and

20 inches, and hypotenuse length
25 inches
O A 1950 in.
B. 2100 in.?
C. 2400 in.
D. 2800 in.?
Mathematics
1 answer:
saveliy_v [14]4 years ago
8 0

Answer:

The answer would be B.2100

Step-by-step explanation:

To find the surface area of a triangular prism, first find the lateral area. The lateral area is the product of the perimeter of the base and the height. The perimeter of the base is 15 in.+20 in.+25 in.=60 in., so the lateral area is 60 in.⋅30 in.=1800 in.2. The surface area of any prism is the lateral area plus the base area. Because each base is a right triangle, the area of each base is 12bh. Because the legs of the right triangle are perpendicular, you can use one of them as the base and one as the height. So, the base area is 12⋅20 in.⋅15 in.=150 in.2. There are two bases, so the surface area is 1800 in.2+150 in.2+150 in.2=2100 in.2.

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Las direcciones dadas en el enunciado significan lo siguiente:

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E57ºN - <em>57º al norte del este.</em>

Vectorialmente hablando, cada dirección es la siguiente:

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\theta = \cos^{-1} \frac{A\,\bullet \,B}{\|A\|\cdot \|B\|}

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\|A\| - Norma de A(x,y).

\|B\| - Norma de B(x,y).

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\theta = \cos^{-1} \frac{(0.530)\cdot (0.545)+(-0.848)\cdot (0.839)}{(1)\cdot (1)}

\theta \approx 115^{\circ}

El ángulo formado entre las dos direcciones es aproximadamente 115º.

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