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2 years ago

Which equation could have been used to create this table?

Mathematics

2 answers:

Lyrx [107]2 years ago

8 0

Answer:

y = 3x

Step-by-step explanation:

(1,3) (2,6)

The first step is to find the rate of change ( or slope)

m = (y2-y1)/(x2-x1)

m = (6-3)/(2-1)

m = 3/1

m = 3

Then we need to use the point slope form of the equation of a line

y-y1 = m(x-x1)

y-3 = 3(x-1)

Distribute the 3

y-3 = 3x-3

Add 3 to each side

y-3+3 = 3x-3+3

y = 3x

kkurt [141]2 years ago

4 0

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (1, 3) and (2, 6). Substitute:

$m=\dfrac{6-3}{2-1}=\dfrac{3}{1}=3$

Therefore we have:

$y=3x+b$

Put the coordinates of the point (1, 3) to the equation and calculate a value of b:

$3=3(1)+b$

$3=3+b$ <em>subtract 3 from both sides</em>

$0=b\to b=0$

<h3>Answer: y = 3x + 0 = 3x</h3>

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3 years ago

An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

The sample size n = 320 passengers

The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > -1.914 )$

From the z-table

$P(Z > -1.914 ) = 0.97219$

$P(X >300 ) = 0.97219$

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2 years ago

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3+(-5)x=19
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