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vova2212 [387]
3 years ago
6

Which equation could have been used to create this table?

Mathematics
2 answers:
Lyrx [107]3 years ago
8 0

Answer:

y = 3x

Step-by-step explanation:

(1,3) (2,6)

The first step is to find the rate of change ( or slope)

m = (y2-y1)/(x2-x1)

m = (6-3)/(2-1)

m = 3/1

m = 3

Then  we need to use the point slope form of the equation of a line

y-y1 = m(x-x1)

y-3 = 3(x-1)

Distribute the 3

y-3 = 3x-3

Add 3 to each side

y-3+3 = 3x-3+3

y = 3x

kkurt [141]3 years ago
4 0

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (1, 3) and (2, 6). Substitute:

m=\dfrac{6-3}{2-1}=\dfrac{3}{1}=3

Therefore we have:

y=3x+b

Put the coordinates of the point (1, 3) to the equation and calculate a value of b:

3=3(1)+b

3=3+b            <em>subtract 3 from both sides</em>

0=b\to b=0

<h3>Answer: y = 3x + 0 = 3x</h3>
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