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Alenkasestr [34]
4 years ago
10

Evaluate the expression when x=-6. x² +5x-3

Mathematics
2 answers:
V125BC [204]4 years ago
8 0
You are to evaluate   x^2 + 5x - 3 for x=-6

Replace each occurrence of x with parentheses:   (   )^2 + 5(   ) - 3.
Now write -6 inside each of the two sets of parentheses.

Evaluate   (    )^2 and 5(     )

Add together the 3 terms.
Alona [7]4 years ago
5 0
5=30-3=27+-36=-9 amswers negfative 9
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aleksley [76]

Given:

The expression is:

(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}

To find:

The value of the given expression when x=64 and y=27.

Solution:

We have,

(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}

Putting x=64 and y=27, we get

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It can be written as

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