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3 years ago

What is the average rate of change for the quadratic function from x=-1 to x=4?

Mathematics

1 answer:

Mazyrski [523]3 years ago

7 0

Answer:

Step-by-step explanation:

f(x) = x^2 - 2x - 4

when x = -1, f(-1) = (-1)^2 - 2(-1) - 4 = 1 + 2 - 4 = -1

when x = 4, f(4) = (4)^2 - 2(4) - 4 = 16 - 8 - 4 = 4

The average rate of change from x = -1 to x = 4:

f(4) - f(-1) 4 - (-1) 5

---------------- = -----------------= -------- = 1

x4 - x1 4 - (-1) 5

Answer

The average rate of change = 1

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Fred owns an oil change shop and is doing some research on car colors. Saturdays are

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2 years ago

Carlos cut StartFraction 5 Over 12 EndFraction of a yard of cloth into 5 pieces of equal length. What was the length of each pie

erastovalidia [21]

Answer:

Each piece of cloth is (1/12) of a yard long.

Step-by-step explanation:

Carlus cut 5/12 of a yard of cloth into 5 pieces of equal length.

To find the length of each piece of cloth, we need to find the quotient between the length of the piece of cloth, and the number of pieces in which we divide it.

This is:

length = $\frac{(5/12)yd}{5} = \frac{5yd}{12*5} = \frac{1yd}{12} \frac{5}{5} = \frac{1 }{12} yd$

This means that the length of each piece of cloth is (1/12) of a yard long.

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3 years ago

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vodka [1.7K]

Answer:

The true statements are (D) and (E). This is a square with sides equal to 5 units so that means that its perimeter is 4×(5 units) or 20 units and its area is (5 units)×(5 units) or 25 units^2.

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3 years ago

determine the value of x for which r parallels s. then find the measure of angle 1 and the measure of angle 2measure angle 1= 50

Maslowich

According to the picture, angles 1 and 2 have the same measure because they are corresponding angles. Make equal both expressions for 1 and 2 and find x.

$\begin{gathered} 50-2x=110-42x \\ 42x-2x=110-50 \\ 40x=60 \\ x=\frac{60}{40} \\ x=\frac{3}{2} \end{gathered}$

x is 3/2. Replace this value in both expression to find the measure of each angle.

$\begin{gathered} \measuredangle1=50-2x \\ \measuredangle1=50-2(\frac{3}{2}) \\ \measuredangle1=50-3 \\ \measuredangle1=47 \\ \measuredangle2=110-42x \\ \measuredangle2=110-42(\frac{3}{2}) \\ \measuredangle2=110-63 \\ \measuredangle2=47 \end{gathered}$

The measure of these angles is 47°

7 0

1 year ago

In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en

jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

Step(i):-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in Swahili language

n(S) = 125

The probability that the fluent in Swahili language

$P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333$

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in English language

$P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9$

n(E∩S) = 95

The probability that the fluent in English and Swahili

$P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633$

Step(ii):-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

= 0.833+0.9-0.633

= 1.1

Final answer:-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0

2 years ago