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Morgarella [4.7K]

3 years ago

15

Jim earns $1,600 per month after taxes. He is working on his budget and has the first three categories finished.

2 answers:

Shkiper50 [21]3 years ago

7 0

B.

He has used the highest recommended percentages to calculate the amounts for the three categories.

ivann1987 [24]3 years ago

6 0

<span>He is budgeting too much for transportation. He has used the highest recommended percentages to calculate the amounts for the three categories. He is budgeting too much for housing. He has used the lowest recommended percentages to calculate the amounts for the three categories. hope this helps :)</span>

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What is the greatest common factor of 20x6y+40x4y2−10x5y5 ?

mestny [16]

The greatest common factor: 20x^6y 40x^4y^2 10x^5y^5 is 10x^4y.
20x^6y = 10x^4y*2x^2
40x^4y^2 = 10x^4y*4y
10x^5y^5 = 10x^4y*y^4

8 0

4 years ago

Rylee is baking cupcakes for a bake sale. She spends $35 on supplies and she plans to sell the cupcakes for $2.50 each. How many

Setler [38]

Answer:

44 cupcakes

Step-by-step explanation:

Since she spent $35, and she wants to profit $75, she needs to make $110.

110/2.5 = 44

6 0

3 years ago

janice wants to jog 3.25 miles on the treadmill she has jogged 1.63 miles how much farther does she have to jog to meet her goal

Mumz [18]

$3.25 - 1.63 = 1.62$
1.62 miles to go to reach her goal.

4 0

3 years ago

Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10

natka813 [3]

ANSWER

$( \frac{2}{3} , \frac{1}{5} )$

EXPLANATION

The first equation is

$\frac{1}{2} x - \frac{3}{4} y = \frac{11}{60} ...(1)$

The second equation is

$\frac{2}{5} x + \frac{1}{6} y = \frac{3}{10} ...(2)$

We want to eliminate y, so we multiply the first equation by

$\frac{4}{5}$

$\frac{4}{5} \times \frac{1}{2} x - \frac{4}{5} \times \frac{3}{4} y = \frac{11}{60} \times \frac{4}{5}$

$\frac{2}{5} x - \frac{3}{5} y = \frac{11}{75} ...(3)$

We now subtract equation (3) from (2)

$(\frac{2}{3} x - \frac{2}{3} x )+ ( \frac{1}{6} y - - \frac{3}{5}y ) =( \frac{3}{10} - \frac{11}{75} )$

$\frac{1}{6} y + \frac{3}{5}y =\frac{3}{10} - \frac{11}{75}$

$\frac{23}{30}y = \frac{23}{150}$

Multiply both sides by

$\frac{30}{23}$

$\implies \: \frac{30}{23} \times \frac{23}{30}y= \frac{23}{150} \times \frac{30}{23}$

$\implies \: y = \frac{1}{5}$

Substitute into the first equation to solve for x .

$\frac{1}{2} x - \frac{3}{4} \times \frac{1}{5} = \frac{11}{60}$

Multiply to obtain

$\frac{1}{2} x - \frac{3}{20} = \frac{11}{60}$

$\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}$

$\frac{1}{2} x = \frac{1}{3}$

Multiply both sides by 2.

$2 \times \frac{1}{2} x =2 \times \frac{1}{3}$

$x = \frac{2}{3}$

The solution is

$( \frac{2}{3} , \frac{1}{5} )$

5 0

3 years ago

Read 2 more answers

Have to turn in in 6 mins. please help me. thank you

finlep [7]

Answer:

6

Step-by-step explanation:

all sides of a square are equal

5 0

3 years ago

Read 2 more answers