What is the outlier in the following data set:<br>
15,11,10,8,9,1,8,7,5,4,2,3, and 37?
NeTakaya
Step-by-step explanation:
The steps to find an outlier:
1. Put the data in numerical order.
2. Find the median.
3. Find the medians for the top and bottom parts of the data. This divides the data into 4 equal parts.
The median with the smallest value is called Q1. The median for all the values - usually just called the median is also called Q2. The median with the largest value is Q3.
4. Subtract...Q3 - Q1. This value is the InterQuartileRange or IQR. Remember that the range means taking the largest minus the smallest. This is a special range having to do with the quartiles.
5. Multiply...1.5 * IQR
6. Take your answer from #5 and do 2 things with it. A). Subtract it from Q1 and B) Additional to Q3.
7. Look at all your data points. If any are SMALLER than Q1 - 1.5 *IQR, they are outliers. If any are LARGER than Q3 + 1.5 *IQR, they are also outliers.
For your data....the median, Q2 is
(43+38)/2 = 40.5.
Q1 = (30+26)/2 = 28.
Q3 = (54+52)/2 = 53
The IQR is 53 - 28 = 25
1.5 * IQR = 37.5
Q1 - 37.5 = 28 - 37.5 = -9.5. There is no data value less than -9.5.
Q3 + 37.5 = 53 + 37.5 = 90.5. there is no data value greater than 90.5.
My conclusion is that there are no outliers in this data.
I hope this helps!
Answer: $7142.86
Step-by-step explanation:
Let the amount to be invested in the bond be represented by y.
Based on this, the amount to be invested in the CD will be: = 50000 - y.
From the information given, yearly interest on bond is 12%, this will be:
= 12% × y = 0.12 × y = 0.12y
Also, interest on CD will be:
= 5% × (50000 - y)
= 0.05(50000 - y)
Then, the equation to get the amount to be invested in bond will be:
0.12y + 0.05(50000 - y) = 3000
0.12y + 2500 - 0.05y = 3000
0.12y - 0.05y = 3000 - 2500
0.07y = 500
y = 500/0.07
y = 7142.8571
y = 7142.86
The amount to be invested in bond will be $7142.86
Since we know that 2/8 equals 1/4, we can simply use that unit rate to calculate that 6/8 = 3/4.
Answer:
A
Step-by-step explanation:
Let x= number of visits she makes
9(number of visits she makes) + 32 (less than or equal to) <= 122
9x+32<= 122
